Math Problem Statement

the image is figure 1: Compute the x- and y-components of the vectors A⃗ 𝐴→, B⃗ 𝐵→, C⃗ 𝐶→, and D⃗ 𝐷→ in (Figure 1).

Express your answer in meters.

Ax,Ay =

Solution

To find the xx- and yy-components of the vectors A\vec{A}, B\vec{B}, C\vec{C}, and D\vec{D} from the given diagram, we will use trigonometry. For a vector V\vec{V} with magnitude VV and angle θ\theta relative to the positive xx-axis, the components are:

Vx=Vcos(θ)V_x = V \cos(\theta) Vy=Vsin(θ)V_y = V \sin(\theta)

Let's calculate the components for each vector:

1. Vector A\vec{A}:

  • Magnitude: A=8.0m|\vec{A}| = 8.0 \, \text{m}
  • Angle: θA=270\theta_A = 270^\circ (or 90-90^\circ) with respect to the positive xx-axis.

Ax=8.0×cos(270)=8.0×0=0mA_x = 8.0 \times \cos(270^\circ) = 8.0 \times 0 = 0 \, \text{m} Ay=8.0×sin(270)=8.0×(1)=8.0mA_y = 8.0 \times \sin(270^\circ) = 8.0 \times (-1) = -8.0 \, \text{m}

2. Vector B\vec{B}:

  • Magnitude: B=15.0m|\vec{B}| = 15.0 \, \text{m}
  • Angle: θB=30\theta_B = 30^\circ with respect to the positive xx-axis.

Bx=15.0×cos(30)=15.0×32=12.99mB_x = 15.0 \times \cos(30^\circ) = 15.0 \times \frac{\sqrt{3}}{2} = 12.99 \, \text{m} By=15.0×sin(30)=15.0×12=7.5mB_y = 15.0 \times \sin(30^\circ) = 15.0 \times \frac{1}{2} = 7.5 \, \text{m}

3. Vector C\vec{C}:

  • Magnitude: C=12.0m|\vec{C}| = 12.0 \, \text{m}
  • Angle: θC=18025=155\theta_C = 180^\circ - 25^\circ = 155^\circ with respect to the positive xx-axis.

Cx=12.0×cos(155)=12.0×(0.9063)=10.88mC_x = 12.0 \times \cos(155^\circ) = 12.0 \times (-0.9063) = -10.88 \, \text{m} Cy=12.0×sin(155)=12.0×0.4226=5.07mC_y = 12.0 \times \sin(155^\circ) = 12.0 \times 0.4226 = 5.07 \, \text{m}

4. Vector D\vec{D}:

  • Magnitude: D=10.0m|\vec{D}| = 10.0 \, \text{m}
  • Angle: θD=53\theta_D = 53^\circ with respect to the positive xx-axis.

Dx=10.0×cos(53)=10.0×0.6018=6.02mD_x = 10.0 \times \cos(53^\circ) = 10.0 \times 0.6018 = 6.02 \, \text{m} Dy=10.0×sin(53)=10.0×0.7986=7.99mD_y = 10.0 \times \sin(53^\circ) = 10.0 \times 0.7986 = 7.99 \, \text{m}

Summary:

  • Ax=0m,Ay=8.0mA_x = 0 \, \text{m}, \, A_y = -8.0 \, \text{m}
  • Bx=12.99m,By=7.5mB_x = 12.99 \, \text{m}, \, B_y = 7.5 \, \text{m}
  • Cx=10.88m,Cy=5.07mC_x = -10.88 \, \text{m}, \, C_y = 5.07 \, \text{m}
  • Dx=6.02m,Dy=7.99mD_x = 6.02 \, \text{m}, \, D_y = 7.99 \, \text{m}

Would you like more details or have any other questions?

Here are some follow-up questions:

  1. How can you find the resultant vector from these components?
  2. What is the significance of the angles used in these calculations?
  3. How would the components change if vector AA was rotated by 90 degrees?
  4. What is the process to calculate the magnitude of a vector from its components?
  5. How do you add two vectors given in component form?

Tip: Always check the quadrant of the angle to determine the correct signs for the components.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Vector Components

Formulas

Component form of vectors: $V_x = V \cos(\theta)$, $V_y = V \sin(\theta)$

Theorems

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Suitable Grade Level

High School