Math Problem Statement

Fifteen people are randomly assigned, so that 5 people exercise in the morning, afternoon, or night. After 8 weeks, their weight loss is measured in pounds. Compute SS between.

Morning Morning2 Afternoon Afternoon2 Night Night2 10 100 8 64 6 36 8 64 8 64 7 49 7 49 9 81 5 25 5 25 7 49 4 16 9 81 7 49 5 25

Solution

To compute SS between (Sum of Squares Between Groups), we follow these steps:

Formula:

SSbetween=k=1gnk(XˉkXˉtotal)2SS_{\text{between}} = \sum_{k=1}^g n_k (\bar{X}_k - \bar{X}_{\text{total}})^2

Where:

  • gg: Number of groups (3 in this case: Morning, Afternoon, Night)
  • nkn_k: Number of participants in each group (5 each)
  • Xˉk\bar{X}_k: Mean of each group
  • Xˉtotal\bar{X}_{\text{total}}: Overall mean
  • SSbetweenSS_{\text{between}}: Variance due to differences between groups

Step-by-step Calculation:

1. Compute the group means (Xˉk\bar{X}_k):

  • Morning Mean (Xˉmorning\bar{X}_{\text{morning}}): Xˉmorning=10+8+7+5+95=395=7.8\bar{X}_{\text{morning}} = \frac{10 + 8 + 7 + 5 + 9}{5} = \frac{39}{5} = 7.8

  • Afternoon Mean (Xˉafternoon\bar{X}_{\text{afternoon}}): Xˉafternoon=8+8+9+7+75=395=7.8\bar{X}_{\text{afternoon}} = \frac{8 + 8 + 9 + 7 + 7}{5} = \frac{39}{5} = 7.8

  • Night Mean (Xˉnight\bar{X}_{\text{night}}): Xˉnight=6+7+5+4+55=275=5.4\bar{X}_{\text{night}} = \frac{6 + 7 + 5 + 4 + 5}{5} = \frac{27}{5} = 5.4


2. Compute the overall mean (Xˉtotal\bar{X}_{\text{total}}):

Xˉtotal=Sum of all weightsTotal number of participants\bar{X}_{\text{total}} = \frac{\text{Sum of all weights}}{\text{Total number of participants}}

Sum of all weights: 10+8+7+5+9+8+8+9+7+7+6+7+5+4+5=10510 + 8 + 7 + 5 + 9 + 8 + 8 + 9 + 7 + 7 + 6 + 7 + 5 + 4 + 5 = 105

Xˉtotal=10515=7.0\bar{X}_{\text{total}} = \frac{105}{15} = 7.0


3. Compute SSbetweenSS_{\text{between}}:

For each group: SSbetween=nk(XˉkXˉtotal)2SS_{\text{between}} = n_k (\bar{X}_k - \bar{X}_{\text{total}})^2

  • Morning: SSmorning=5(7.87.0)2=5(0.8)2=5(0.64)=3.2SS_{\text{morning}} = 5 (7.8 - 7.0)^2 = 5 (0.8)^2 = 5 (0.64) = 3.2

  • Afternoon: SSafternoon=5(7.87.0)2=5(0.8)2=5(0.64)=3.2SS_{\text{afternoon}} = 5 (7.8 - 7.0)^2 = 5 (0.8)^2 = 5 (0.64) = 3.2

  • Night: SSnight=5(5.47.0)2=5(1.6)2=5(2.56)=12.8SS_{\text{night}} = 5 (5.4 - 7.0)^2 = 5 (-1.6)^2 = 5 (2.56) = 12.8


4. Add the components:

SSbetween=SSmorning+SSafternoon+SSnightSS_{\text{between}} = SS_{\text{morning}} + SS_{\text{afternoon}} + SS_{\text{night}}

SSbetween=3.2+3.2+12.8=19.2SS_{\text{between}} = 3.2 + 3.2 + 12.8 = 19.2


Final Answer:

SSbetween=19.2SS_{\text{between}} = 19.2

Would you like further details or clarification? Here are five follow-up questions and one tip:


  1. What are the differences between SSbetweenSS_{\text{between}} and SSwithinSS_{\text{within}}?
  2. How is SStotalSS_{\text{total}} related to SSbetweenSS_{\text{between}} and SSwithinSS_{\text{within}}?
  3. Why do we square the deviations when computing SS values?
  4. Can you calculate the F-ratio from the SSbetweenSS_{\text{between}} and SSwithinSS_{\text{within}}?
  5. How would the SSbetweenSS_{\text{between}} change if one group had a higher mean?

Tip: Always check that your calculations are consistent with the group sample sizes and overall totals to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Statistics
Analysis of Variance (ANOVA)
Sum of Squares

Formulas

SS_between = ∑(n_k (X̄_k - X̄_total)^2)
Mean = Sum of values / Number of values

Theorems

Partitioning of Sum of Squares in ANOVA

Suitable Grade Level

Undergraduate Level