Math Problem Statement

Compute the domain of the function f(x) = sqrt[((14 - x)^2) / (7 - x)].

Solution

We are asked to compute the domain of the function

f(x)=(14x)27x.f(x) = \sqrt{\frac{(14 - x)^2}{7 - x}}.

Domain Constraints:

  1. Square root constraint: The expression inside the square root must be non-negative, i.e., (14x)27x0.\frac{(14 - x)^2}{7 - x} \geq 0.

  2. Denominator constraint: The denominator 7x7 - x cannot be zero, meaning: x7.x \neq 7.

Let’s analyze these constraints step by step:

1. Simplifying the expression:

Since (14x)2(14 - x)^2 is a square term, it is always non-negative. So, we only need to focus on the sign of 7x7 - x.

  • For the fraction (14x)27x\frac{(14 - x)^2}{7 - x} to be non-negative, 7x7 - x must be positive or negative appropriately.

  • 7x>0x<77 - x > 0 \Rightarrow x < 7. In this case, the entire expression is non-negative because the numerator is non-negative.

2. Exclusion of x=7x = 7:

As mentioned, the denominator becomes zero when x=7x = 7, which leads to an undefined expression. So, x=7x = 7 is excluded from the domain.

3. Handling x=14x = 14:

At x=14x = 14, (14x)2=0(14 - x)^2 = 0, making the entire expression equal to 0, which is valid. Therefore, x=14x = 14 is part of the domain.

Final domain:

  • The function is defined for all x<7x < 7 (due to the denominator constraint), and for x=14x = 14.
  • The domain is thus: (,7){14}.(-\infty, 7) \cup \{14\}.

Answer:

The correct domain of the function is (,7]{14}(-\infty, 7] \cup \{14\}, which corresponds to the first option in the list: ],7]{14}.] -\infty, 7] \cup \{14\}.


Would you like further details on any of these steps? Here are five related questions you could explore:

  1. How do we handle other types of square root functions with different polynomials in the numerator?
  2. What if the numerator of the expression had a different sign pattern?
  3. How does the domain change if the exponent on 14x14 - x is odd rather than even?
  4. Can you give an example of a function where both the numerator and denominator contribute equally to domain restrictions?
  5. How does the addition of complex numbers impact the domain of square root functions?

Tip: Always double-check both the numerator and denominator when computing domains for rational functions!

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Math Problem Analysis

Mathematical Concepts

Functions
Square Roots
Inequalities

Formulas

f(x) = sqrt[((14 - x)^2) / (7 - x)]
Square root constraint: f(x) ≥ 0
Denominator constraint: 7 - x ≠ 0

Theorems

Domain of a square root function must be non-negative
Division by zero exclusion

Suitable Grade Level

Grades 9-12