Math Problem Statement

Suppose you make a deposit of ​$100 at the beginning of every year into an account. At the beginning of the first​ year, the value of the account will be 100 ​dollars; at the beginning of the second​ year, the value of the​ account, in​ dollars, can be found by the given equation. Complete parts​ (a) and​ (b) below. ModifyingBelow ModifyingBelow 100 plus 100 r with brace With Value of 1 st deposit plus ModifyingBelow ModifyingBelow 100 with brace With Value of 2 nd deposit equals 100 left parenthesis 1 plus r right parenthesis plus 100 equals 100 r plus 200 Question content area bottom Part 1 ​(a) Verify that the value of the account at the beginning of the third year is Upper T left parenthesis r right parenthesis equals 100 r squared plus 300 r plus 300. Part 2 Choose the correct answer below. A.100 left parenthesis 1 plus r right parenthesis left parenthesis 1 plus r right parenthesis plus 100 left parenthesis 1 plus r right parenthesis plus 100 r equals 100 r squared plus 300 r plus 100 plus 100 r plus 100 equals 100 r squared plus 300 r plus 300 100 left parenthesis 1 plus r right parenthesis left parenthesis 1 plus r right parenthesis plus 100 left parenthesis 1 plus r right parenthesis plus 100 r equals 100 r squared plus 300 r plus 100 plus 100 r plus 100 equals 100 r squared plus 300 r plus 300 B.100 left parenthesis 1 plus r right parenthesis left parenthesis 1 plus r right parenthesis plus 100 left parenthesis 1 plus r right parenthesis plus 100 equals 100 r squared plus 200 r plus 100 plus 100 r plus 100 plus 100 equals 100 r squared plus 300 r plus 300 100 left parenthesis 1 plus r right parenthesis left parenthesis 1 plus r right parenthesis plus 100 left parenthesis 1 plus r right parenthesis plus 100 equals 100 r squared plus 200 r plus 100 plus 100 r plus 100 plus 100 equals 100 r squared plus 300 r plus 300 C.100 left parenthesis 1 plus r right parenthesis left parenthesis 1 plus r right parenthesis plus 100 left parenthesis 1 plus r squared right parenthesis plus 100 equals 100 r squared plus 300 r plus 100 plus 100 r plus 100 plus 100 equals 100 r squared plus 300 r plus 300 100 left parenthesis 1 plus r right parenthesis left parenthesis 1 plus r right parenthesis plus 100 left parenthesis 1 plus r squared right parenthesis plus 100 equals 100 r squared plus 300 r plus 100 plus 100 r plus 100 plus 100 equals 100 r squared plus 300 r plus 300

Solution

Let's break down both parts systematically:

Part 1 (a): Verify the value of the account at the beginning of the third year.

At the beginning of the first year, you deposit $100, and that $100 grows by rr each year. By the beginning of the third year, the value of the account is the sum of the compounded value of each deposit.

Step-by-step breakdown:

  1. First deposit (made at the beginning of year 1):

    • This deposit grows for 2 years.
    • After 2 years, its value is: 100(1+r)2=100(1+2r+r2)=100r2+200r+100100(1 + r)^2 = 100(1 + 2r + r^2) = 100r^2 + 200r + 100
  2. Second deposit (made at the beginning of year 2):

    • This deposit grows for 1 year.
    • After 1 year, its value is: 100(1+r)=100r+100100(1 + r) = 100r + 100
  3. Third deposit (made at the beginning of year 3):

    • This deposit does not grow because it is made at the start of the third year, so its value remains: 100100

Now, add all these values together to get the total at the beginning of the third year: 100r2+200r+100(from 1st deposit)100r^2 + 200r + 100 \quad \text{(from 1st deposit)} +100r+100(from 2nd deposit)+ 100r + 100 \quad \text{(from 2nd deposit)} +100(from 3rd deposit)+ 100 \quad \text{(from 3rd deposit)} Simplify: 100r2+(200r+100r)+(100+100+100)=100r2+300r+300100r^2 + (200r + 100r) + (100 + 100 + 100) = 100r^2 + 300r + 300

Thus, the value of the account at the beginning of the third year is: T(r)=100r2+300r+300T(r) = 100r^2 + 300r + 300

This verifies the equation provided.


Part 2: Choose the correct answer.

We need to identify which option matches the calculation done above. The correct equation is:

100(1+r)2+100(1+r)+100100(1 + r)^2 + 100(1 + r) + 100

Let's evaluate the expressions in the given choices:

  • Option A: 100(1+r)(1+r)+100(1+r)+100100(1 + r)(1 + r) + 100(1 + r) + 100 This simplifies to: 100(1+r)2+100(1+r)+100=100r2+200r+100+100r+100=100r2+300r+300100(1 + r)^2 + 100(1 + r) + 100 = 100r^2 + 200r + 100 + 100r + 100 = 100r^2 + 300r + 300 This matches our expression. Hence, Option A is the correct answer.

Would you like further details or clarifications on any step? Let me know!

Related Questions:

  1. What if the interest rate is compounded monthly instead of yearly?
  2. How would the formula change if the deposit amounts were different each year?
  3. Can this method be generalized to nn years? What would the total amount be after nn years?
  4. What happens to the total amount if r=0r = 0? Does the formula still work?
  5. How does the account value change if deposits are made at the end of each year instead?

Tip:

Always ensure that when handling compound interest problems, the growth periods for each deposit are correctly tracked. The key difference is how long each deposit has been earning interest.

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Math Problem Analysis

Mathematical Concepts

Compound Interest
Quadratic Equations
Algebra

Formulas

Compound interest formula for deposits: A = P(1 + r)^n
Quadratic expression: ax^2 + bx + c

Theorems

Basic compound interest theorem
Quadratic equation expansion

Suitable Grade Level

Grades 10-12