In this scenario, we have a combination of compound interest growth and periodic withdrawals. The problem involves a mutual fund with an initial investment, a specific annual compound interest rate, and regular monthly withdrawals. Here's how we can break it down:

Known Values:

• Initial investment (P): ₹20,000,000 (20 million rupees)
• Interest rate (r): 17.07% per annum, compounded annually.
• Time (t): 10 years
• Monthly withdrawal (W): ₹100,000 (1 lakh rupees)
• Number of withdrawals: 120 (since 12 months per year for 10 years)

Step 1: Growth Due to Compound Interest

The formula for compound interest compounded annually is:

$A = P \times \left(1 + \frac{r}{100}\right)^t$

Where:

• $A$ is the amount after time $t$,
• $P$ is the principal (initial investment),
• $r$ is the interest rate per annum,
• $t$ is the time in years.

So, the investment will grow as:

$A = 20,000,000 \times \left(1 + \frac{17.07}{100}\right)^{10}$

Step 2: Adjust for Monthly Withdrawals

Since there are monthly withdrawals of ₹100,000, we need to adjust for that by considering the effective balance each year. These withdrawals affect the total interest growth.

To calculate this precisely, we would need to account for both:

1. The growth of the initial amount due to compounding interest.
2. The depletion of the total balance due to monthly withdrawals.

To model this exactly, we would use a form of the annuity withdrawal formula, adjusting for the compounded interest.

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Here are 5 related questions to expand your understanding:

1. How is compound interest calculated with varying withdrawal rates?
2. What is the effect of withdrawing at different intervals on compound interest?
3. Can reinvestment of withdrawn funds improve overall returns?
4. How does inflation impact the real value of returns from an investment like this?
5. What are other investment strategies to optimize long-term returns?

Tip: Compounding works best when left untouched; minimizing withdrawals can maximize future returns!