Math Problem Statement

A businessman has done an investment of Rs.200,000.00 on a new business expecting a 5% interest compounded yearly. How much he totally would earn in 6 years

Solution

To calculate how much the businessman would earn in total after 6 years, we can use the formula for compound interest:

A=P(1+rn)ntA = P \left( 1 + \frac{r}{n} \right)^{nt}

Where:

  • AA is the amount of money accumulated after tt years, including interest.
  • PP is the principal amount (Rs. 200,000).
  • rr is the annual interest rate (5% or 0.05).
  • nn is the number of times the interest is compounded per year (since it's yearly, n=1n = 1).
  • tt is the number of years (6 years).

Substituting the values into the formula:

A=200,000(1+0.051)1×6A = 200,000 \left( 1 + \frac{0.05}{1} \right)^{1 \times 6} A=200,000(1+0.05)6A = 200,000 \left( 1 + 0.05 \right)^{6} A=200,000(1.05)6A = 200,000 \left( 1.05 \right)^{6} A=200,000×1.3401A = 200,000 \times 1.3401 A268,020A \approx 268,020

So, after 6 years, the businessman will have a total amount of Rs. 268,020.

The total earnings (interest earned) are:

Total Earnings=AP=268,020200,000=68,020\text{Total Earnings} = A - P = 268,020 - 200,000 = 68,020

Thus, the businessman would earn Rs. 68,020 in total over 6 years.

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Here are 5 related questions:

  1. How would the total amount change if the interest were compounded quarterly?
  2. What would the total amount be if the interest rate were 6% instead of 5%?
  3. How do you calculate the compound interest when the principal is increased every year?
  4. What is the difference between simple and compound interest over a period of time?
  5. How does the number of compounding periods (annually, quarterly, monthly) affect the total amount?

Tip: The more frequently interest is compounded, the greater the amount will grow over time.

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Math Problem Analysis

Mathematical Concepts

Compound Interest
Exponential Growth
Finance Mathematics

Formulas

Compound Interest Formula: A = P (1 + r/n)^(nt)

Theorems

Exponential Growth Principle

Suitable Grade Level

Grades 9-12