Math Problem Statement

Ram invested 50,000 rupees at 14% p.a. compounded half-yearly. What is the amount that Ram will get at the end of 9 months.

Solution

We are given:

  • Principal (P) = ₹50,000
  • Annual interest rate (R) = 14% p.a. (compounded half-yearly)
  • Time (T) = 9 months
  • Compound frequency: half-yearly

Since the interest is compounded half-yearly, we need to adjust the rate and time accordingly:

  1. Half-yearly rate of interest (R): R=142=7% per half-yearR = \frac{14}{2} = 7\% \text{ per half-year}

  2. Number of half-yearly periods (n): n=9 months6 months per half-year=1.5 half-year periodsn = \frac{9 \text{ months}}{6 \text{ months per half-year}} = 1.5 \text{ half-year periods}

Now, we can use the compound interest formula:

A=P(1+R100)nA = P \left(1 + \frac{R}{100}\right)^n

Where:

  • AA is the amount
  • PP is the principal
  • RR is the interest rate per period
  • nn is the number of periods

Substituting the values into the formula:

A=50,000(1+7100)1.5A = 50,000 \left(1 + \frac{7}{100}\right)^{1.5}

Let’s compute the final amount.The amount that Ram will receive at the end of 9 months, with interest compounded half-yearly, is approximately ₹55,340.83.

Would you like further details or clarifications?

Here are 5 related questions for practice:

  1. How would the amount change if the interest rate was compounded quarterly instead?
  2. What would be the amount if the time period was extended to 1 year?
  3. How does compounding frequency affect the total amount received?
  4. If the interest rate were 10% instead of 14%, what would be the new amount?
  5. What is the difference between simple and compound interest over the same period?

Tip: The more frequent the compounding, the greater the total amount of interest earned!

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Math Problem Analysis

Mathematical Concepts

Compound Interest
Time and Interest Rate Adjustments

Formulas

A = P(1 + R/100)^n

Theorems

Compound Interest Theorem

Suitable Grade Level

Grades 9-11