Math Problem Statement

Let z be a complex number that satisfies the equation, then what is the value of the imaginary part of z in the equation: \overline{z} + i|z| = 12 + 9i?

Solution

The equation in the image is:

z+iz=12+9i\overline{z} + i|z| = 12 + 9i

Where:

  • zz is a complex number,
  • z\overline{z} is the complex conjugate of zz,
  • ii is the imaginary unit,
  • z|z| is the modulus (magnitude) of zz.

Let z=x+yiz = x + yi, where xx is the real part and yy is the imaginary part of the complex number. Therefore:

  • z=xyi\overline{z} = x - yi (complex conjugate of zz),
  • z=x2+y2|z| = \sqrt{x^2 + y^2} (modulus of zz).

Now, let's substitute these into the equation:

(xyi)+ix2+y2=12+9i(x - yi) + i\sqrt{x^2 + y^2} = 12 + 9i

Separate the real and imaginary parts:

  • Real part: x=12x = 12,
  • Imaginary part: y+x2+y2=9-y + \sqrt{x^2 + y^2} = 9.

Since x=12x = 12, substitute it into the imaginary part equation:

y+122+y2=9-y + \sqrt{12^2 + y^2} = 9

y+144+y2=9-y + \sqrt{144 + y^2} = 9

Now, let's solve for yy.The solution for yy, the imaginary part of zz, is:

y=72=3.5y = \frac{7}{2} = 3.5

So, the value of the imaginary part of zz is 3.53.5.

Would you like any further details or explanations?

Here are 5 related questions to expand on this concept:

  1. How do you calculate the modulus of a complex number?
  2. What is the significance of the complex conjugate in equations like this?
  3. How can you apply this method to solve more general complex number equations?
  4. Why is separating real and imaginary parts essential when solving complex equations?
  5. What are some real-world applications of complex numbers?

Tip: Always ensure you correctly separate real and imaginary parts when solving equations involving complex numbers.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Modulus of Complex Numbers
Complex Conjugate

Formulas

z = x + yi
Complex Conjugate: \overline{z} = x - yi
Modulus: |z| = \sqrt{x^2 + y^2}

Theorems

Complex Conjugate Theorem
Pythagorean Theorem (for modulus)

Suitable Grade Level

Grade 11-12, College level