Math Problem Statement

Rewrite the following complex number in rectangular form.

z=8(cos⁡(5π4)+isin⁡(5π4))z=8(cos(45π​)+isin(45π​))

Solution

Let's break down the given expression step by step.

We have:

z=8(cos(5π4)+isin(5π4))z = 8 \left( \cos\left(\frac{5\pi}{4}\right) + i \sin\left(\frac{5\pi}{4}\right) \right)

and

z=8(cos(45π)+isin(45π))z^* = 8 \left( \cos(45\pi) + i \sin(45\pi) \right)

1. First, simplify zz:

The angle 5π4\frac{5\pi}{4} is located in the third quadrant of the unit circle, where both sine and cosine are negative.

cos(5π4)=22\cos\left(\frac{5\pi}{4}\right) = -\frac{\sqrt{2}}{2} sin(5π4)=22\sin\left(\frac{5\pi}{4}\right) = -\frac{\sqrt{2}}{2}

Thus, zz becomes:

z=8(22+i(22))z = 8 \left( -\frac{\sqrt{2}}{2} + i \left(-\frac{\sqrt{2}}{2}\right) \right) z=8×22+8i×22z = 8 \times -\frac{\sqrt{2}}{2} + 8i \times -\frac{\sqrt{2}}{2} z=424i2z = -4\sqrt{2} - 4i\sqrt{2}

2. Now, simplify zz^*:

The angle 45π45\pi is coterminal with π\pi, since 45πmod2π=π45\pi \mod 2\pi = \pi.

For π\pi:

cos(π)=1,sin(π)=0\cos(\pi) = -1, \quad \sin(\pi) = 0

Thus, zz^* becomes:

z=8(1+i0)z^* = 8(-1 + i \cdot 0) z=8z^* = -8

3. Final expression in rectangular form:

z=424i2,z=8z = -4\sqrt{2} - 4i\sqrt{2}, \quad z^* = -8

If you want further details, feel free to ask!


Here are 5 related questions:

  1. What is the geometric interpretation of a complex number in polar form?
  2. How do you convert between rectangular and polar forms of complex numbers?
  3. What are the properties of complex conjugates?
  4. Why is zz^* based on 45π45\pi simplified to π\pi?
  5. What is the significance of the unit circle when dealing with complex numbers?

Tip: When finding coterminal angles, subtract multiples of 2π2\pi to reduce the angle to one full rotation or less.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Rectangular and Polar Form
Trigonometry

Formulas

z = r(cos(θ) + i sin(θ))
Coterminal angles: θ ± 2πn

Theorems

Polar to Rectangular Conversion
Coterminal Angles

Suitable Grade Level

College-level Mathematics (or Advanced High School)