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The question asks how much farther Daniel's car can travel on one gallon of gas compared to Bo's car. Let's break it down:

1. **Daniel's car**:
   - The equation given is \( y = 31.5x \), where \( y \) is the number of miles Daniel can drive for \( x \) gallons of gas.
   - From this, Daniel can drive **31.5 miles per gallon**.

2. **Bo's car**:
   - Bo uses 9 gallons of gas to drive 256.5 miles.
   - The mileage per gallon for Bo is:
     \[
     \frac{256.5 \text{ miles}}{9 \text{ gallons}} = 28.5 \text{ miles per gallon}.
     \]

3. **Difference**:
   - To find out how much farther Daniel's car can travel on one gallon of gas, subtract Bo's mileage from Daniel's mileage:
     \[
     31.5 \text{ miles per gallon} - 28.5 \text{ miles per gallon} = 3 \text{ miles}.
     \]

Thus, Daniel's car can travel **3 miles farther** per gallon than Bo's car.

Would you like further details or have any additional questions?

Here are five related questions:
1. How would the result change if Daniel’s car drove 35 miles per gallon?
2. If Bo's car improved its mileage to 30 miles per gallon, what would the new difference be?
3. How many miles would Daniel drive on 5 gallons of gas?
4. How many gallons would Bo need to travel 500 miles?
5. How does the cost of gas impact the overall efficiency of these cars?

**Tip**: When comparing fuel efficiencies, always look at the miles-per-gallon ratio for each car to determine the difference effectively.

Two friends, Bo and Daniel, had just bought their first cars. The equation y = 31.5x represents the number of miles, y, that Daniel can drive his car for every x gallons of gas. Bo uses 9 gallons of gas to drive 256.5 miles in his car. How much farther can Daniel's car travel on one gallon of gas than Bo's car?

Learn how to compare fuel efficiency between two cars using linear equations. In this example, Daniel's car drives 31.5 miles per gallon while Bo's car drives 28.5 miles per gallon. The solution calculates how much farther Daniel's car can travel on one gallon of gas.

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