Let's examine each statement based on the graph:

1. $f(0) > g(0)$:
   At $x = 0$, we need to compare the values of $f$ and $g$. From the graph, $f(0) = 0$ (since it intersects the origin), and $g(0) \approx 15$. Therefore, $f(0) < g(0)$, so this statement is false.

2. There are two values of $x$ where $f(x) = g(x)$:
   By inspecting the intersections, $f$ and $g$ intersect at two points: one around $x \approx -2$ and another around $x \approx 2$. So, this statement is true.

3. If $g(x) = 15$, then $x = 1$:
   Checking where $g(x) = 15$, we observe that this occurs at both $x = 1$ and $x = 3$. Thus, the statement "If $g(x) = 15$, then $x = 1$" is incomplete, as there’s another value where $g(x) = 15$. This statement is false.

4. $f(-3) > g(4)$:
   At $x = -3$, $f(-3) \approx 15$, and at $x = 4$, $g(4) = 0$. Therefore, $f(-3) > g(4)$, making this statement true.

Conclusion:

The correct statements are:

• There are two values of $x$ where $f(x) = g(x)$
• $f(-3) > g(4)$

Would you like more detailed explanations for each step?

Here are 5 related questions to deepen understanding:

1. What does it mean when two functions intersect at certain points on a graph?
2. How can you determine function values at specific points without an equation?
3. Why is the inequality $f(0) > g(0)$ false in this case?
4. What method can be used to find all $x$-values where $f(x) = g(x)$?
5. How would the answer change if $f(x)$ and $g(x)$ were altered?

Tip: When comparing function values, focus on the y-values at specific x-values for quick assessments.