Math Problem Statement

divide 11 members into four groups and select compulsory one member from each group then how many sum of all possible combinations we get by selecting any 7 members

Solution

The problem requires us to divide 11 members into 4 groups, then select 1 compulsory member from each group. After this, we need to calculate how many different combinations of 7 members can be selected from the remaining members.

Step-by-Step Breakdown:

  1. Dividing 11 members into 4 groups: Let the groups have the following sizes:

    • Group 1: a1a_1
    • Group 2: a2a_2
    • Group 3: a3a_3
    • Group 4: a4a_4

    Since we have 11 members, we must ensure the group sizes satisfy: a1+a2+a3+a4=11a_1 + a_2 + a_3 + a_4 = 11

  2. Selecting 1 compulsory member from each group: We are asked to choose 1 member from each group. This will account for 4 members in total, leaving 114=711 - 4 = 7 members to choose from the remaining.

  3. Selecting 7 members from the remaining after compulsory selections: Now, we need to calculate the number of ways we can select 7 members from the remaining members. These remaining members would belong to the groups after the 1 compulsory member has been selected from each group.

    To select 7 members, the number of ways depends on how many members are left in each group. Assuming the remaining members form a new set after compulsory selection, the number of possible combinations can be calculated by considering the different sizes of remaining groups.

Would you like a further breakdown of the combinations based on specific group sizes?

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Combinatorics
Group Division
Selection of Members

Formulas

Combination formula C(n, k) = n! / (k!(n-k)!)

Theorems

Basic Counting Principle

Suitable Grade Level

Grades 10-12