Math Problem Statement

The coefficient of variation CV describes the standard deviation as a percent of the mean. Because it has no​ units, you can use the coefficient of variation to compare data with different units. Find the coefficient of variation for each sample data set. What can you​ conclude? CV equals StartFraction Standard deviation Over Mean EndFraction times 100 % 71 218 72 223 77 220 67 207 71 189 80 180 80 181 72 207 77 176 68 177 69 206 80 212 pop-up content ends

Solution

To calculate the coefficient of variation (CV), we need to use the formula:

CV=(Standard DeviationMean)×100%CV = \left( \frac{\text{Standard Deviation}}{\text{Mean}} \right) \times 100\%

You have provided a data set:

71, 218, 72, 223, 77, 220, 67, 207, 71, 189, 80, 180, 80, 181, 72, 207, 77, 176, 68, 177, 69, 206, 80, 212

Let's go through the steps:

Step 1: Calculate the Mean (μ)

The mean is the average of all the data points. We add up all the values and divide by the number of data points.

Mean=Data Pointsn\text{Mean} = \frac{\sum \text{Data Points}}{n}

Where nn is the number of data points. First, let me calculate this.

Step 2: Calculate the Standard Deviation (σ)

The standard deviation measures the spread of data around the mean. The formula for standard deviation is:

σ=(xiμ)2n\sigma = \sqrt{\frac{\sum (x_i - \mu)^2}{n}}

Where:

  • xix_i is each data point
  • μ\mu is the mean
  • nn is the number of data points

I'll calculate both the mean and the standard deviation, and then use the CV formula. numpy as np

Given data set

data = [71, 218, 72, 223, 77, 220, 67, 207, 71, 189, 80, 180, 80, 181, 72, 207, 77, 176, 68, 177, 69, 206, 80, 212]

Calculate mean and standard deviation

mean = np.mean(data) std_dev = np.std(data)

Calculate the Coefficient of Variation (CV)

CV = (std_dev / mean) * 100 mean, std_dev, CVThe calculations give us the following:

  • Mean (μ): 136.67 (rounded to two decimal places)
  • Standard Deviation (σ): 64.24 (rounded to two decimal places)
  • Coefficient of Variation (CV): 47.00%

Conclusion:

The coefficient of variation for this data set is 47.00%. This indicates that the standard deviation is 47% of the mean, suggesting a relatively high variation in the data compared to the mean. Since CV is unitless, you can compare this data set to others with different units of measurement.

Would you like to dive deeper into the concept of CV or how to interpret it further? Feel free to ask!

Here are some related questions:

  1. How can the coefficient of variation help in comparing different data sets?
  2. What are the limitations of using the coefficient of variation?
  3. How does the coefficient of variation behave in data with a small or large standard deviation?
  4. Can the coefficient of variation be used for all types of distributions?
  5. How does changing the mean of a data set affect the coefficient of variation?

Tip: The CV is particularly useful in comparing data sets that are on different scales or have different units of measurement, as it standardizes the variation relative to the mean.

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Math Problem Analysis

Mathematical Concepts

Statistics
Descriptive Statistics
Coefficient of Variation

Formulas

CV = (Standard Deviation / Mean) * 100%

Theorems

Properties of Standard Deviation
Measures of Dispersion

Suitable Grade Level

Grades 9-12