Math Problem Statement

  1. Determine the coordinates of the circumcentre of the triangle.

Solution

To determine the coordinates of the circumcenter of a triangle, we need to follow a few steps:

Step 1: Review the basic properties

The circumcenter is the point of intersection of the perpendicular bisectors of the sides of the triangle. The coordinates of the circumcenter can be calculated using the formula based on the vertices of the triangle.

Step 2: Formula for Circumcenter Coordinates

If the triangle has vertices at A(x1,y1)A(x_1, y_1), B(x2,y2)B(x_2, y_2), and C(x3,y3)C(x_3, y_3), the circumcenter O(x,y)O(x, y) can be found using the following formulas:

D=2×(x1(y2y3)+x2(y3y1)+x3(y1y2))D = 2 \times \left( x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2) \right)

Then, the coordinates of the circumcenter are:

x=(x12+y12)(y2y3)+(x22+y22)(y3y1)+(x32+y32)(y1y2)Dx = \frac{ \left( x_1^2 + y_1^2 \right) (y_2 - y_3) + \left( x_2^2 + y_2^2 \right) (y_3 - y_1) + \left( x_3^2 + y_3^2 \right) (y_1 - y_2) }{D}

y=(x12+y12)(x3x2)+(x22+y22)(x1x3)+(x32+y32)(x2x1)Dy = \frac{ \left( x_1^2 + y_1^2 \right) (x_3 - x_2) + \left( x_2^2 + y_2^2 \right) (x_1 - x_3) + \left( x_3^2 + y_3^2 \right) (x_2 - x_1) }{D}

Step 3: Apply the formula

If you have specific coordinates for the triangle’s vertices, substitute them into the formulas above.

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Math Problem Analysis

Mathematical Concepts

Geometry
Triangle Properties
Circumcenter
Perpendicular Bisectors

Formulas

D = 2 * (x1(y2 - y3) + x2(y3 - y1) + x3(y1 - y2))
x = ((x1^2 + y1^2) * (y2 - y3) + (x2^2 + y2^2) * (y3 - y1) + (x3^2 + y3^2) * (y1 - y2)) / D
y = ((x1^2 + y1^2) * (x3 - x2) + (x2^2 + y2^2) * (x1 - x3) + (x3^2 + y3^2) * (x2 - x1)) / D

Theorems

Circumcenter Theorem
Perpendicular Bisector Theorem

Suitable Grade Level

Grades 10-12