Math Problem Statement
Find circumcenter of a triangle whose vertices are (0, 4) (5, 0) and (- 2, 3).
Solution
The circumcenter of a triangle is the point where the perpendicular bisectors of the sides of the triangle meet. It is equidistant from the vertices of the triangle.
Steps to Find the Circumcenter:
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Identify the vertices of the triangle:
, , . -
Calculate the midpoints of two sides of the triangle:
- Midpoint of :
- Midpoint of :
-
Find the slopes of the sides:
- Slope of :
- Slope of :
-
Calculate the perpendicular slopes:
- Perpendicular slope to :
- Perpendicular slope to :
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Write the equations of the perpendicular bisectors:
- Perpendicular bisector of (passing through ): Simplify:
- Perpendicular bisector of (passing through ): Simplify:
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Solve the two equations to find the intersection point:
- From and , equate:
- Clear fractions by multiplying through by 8: Simplify:
- Substitute into :
Thus, the circumcenter of the triangle is:
Would you like me to elaborate on any step or provide a graphical representation?
Follow-up Questions:
- What are the properties of the circumcenter in different types of triangles?
- Can the circumcenter fall outside the triangle? If yes, when does that occur?
- How is the circumradius related to the circumcenter?
- How do you find the circumcenter of a triangle in 3D space?
- How does the circumcenter relate to the Euler line of a triangle?
Tip: Always double-check calculations when solving equations with fractions to avoid arithmetic errors!
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Math Problem Analysis
Mathematical Concepts
Geometry
Triangles
Coordinate Geometry
Perpendicular Bisectors
Intersection of Lines
Formulas
Midpoint formula: (x1 + x2)/2, (y1 + y2)/2
Slope formula: (y2 - y1)/(x2 - x1)
Perpendicular slope: -1/m
Line equation: y - y1 = m(x - x1)
Theorems
Circumcenter theorem: The point of concurrency of the perpendicular bisectors of a triangle is equidistant from all vertices.
Suitable Grade Level
Grades 9-12
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