Math Problem Statement

An object is moving in anti-clockwise direction along a circle of radius 10cm with an angular velocity of 0.2 radians/second. The circle is on (X,Y) plane with its center at the origin.(i) Assuming that the object starts from the position (10,0) at time t=0, find the X and Ydistances of the object at time t = 8 seconds.(ii) What is the (X,Y) location of the object at t=20 seconds?(iii) How much time it takes to complete one full rotation?

Solution

Let's address each part of the problem step by step.

Part (i): Find the XX and YY distances of the object at t=8t = 8 seconds

Given:

  • Radius of the circle, r=10r = 10 cm
  • Angular velocity, ω=0.2\omega = 0.2 radians/second
  • The object starts at the position (10,0)(10, 0) at t=0t = 0

Step 1: Find the angle covered by the object at t=8t = 8 seconds

The angle θ\theta covered by the object after time tt is given by: θ=ωt\theta = \omega t

Substituting the given values: θ=0.2×8=1.6 radians\theta = 0.2 \times 8 = 1.6 \text{ radians}

Step 2: Determine the XX and YY coordinates at t=8t = 8 seconds

The position of the object in Cartesian coordinates (X,Y)(X, Y) can be found using the parametric equations for circular motion: X=rcos(θ)X = r \cos(\theta) Y=rsin(θ)Y = r \sin(\theta)

Substitute r=10r = 10 cm and θ=1.6\theta = 1.6 radians: X=10cos(1.6)X = 10 \cos(1.6) Y=10sin(1.6)Y = 10 \sin(1.6)

Calculating the values: X10×(0.0292)0.292 cmX \approx 10 \times (-0.0292) \approx -0.292 \text{ cm} Y10×0.99969.996 cmY \approx 10 \times 0.9996 \approx 9.996 \text{ cm}

So, the coordinates at t=8t = 8 seconds are approximately: (X,Y)(0.292,9.996) cm(X, Y) \approx (-0.292, 9.996) \text{ cm}

Part (ii): Find the (X,Y)(X, Y) location of the object at t=20t = 20 seconds

Step 1: Find the angle covered by the object at t=20t = 20 seconds

θ=ωt=0.2×20=4 radians\theta = \omega t = 0.2 \times 20 = 4 \text{ radians}

Step 2: Determine the XX and YY coordinates at t=20t = 20 seconds

Substitute r=10r = 10 cm and θ=4\theta = 4 radians into the parametric equations:

X=10cos(4)X = 10 \cos(4) Y=10sin(4)Y = 10 \sin(4)

Calculating the values: X10×(0.6536)6.536 cmX \approx 10 \times (-0.6536) \approx -6.536 \text{ cm} Y10×(0.7568)7.568 cmY \approx 10 \times (-0.7568) \approx -7.568 \text{ cm}

So, the coordinates at t=20t = 20 seconds are approximately: (X,Y)(6.536,7.568) cm(X, Y) \approx (-6.536, -7.568) \text{ cm}

Part (iii): Find the time taken to complete one full rotation

To complete one full rotation, the object needs to cover an angle of 2π2\pi radians.

The time TT to complete one full rotation can be calculated as: T=2πωT = \frac{2\pi}{\omega}

Substituting ω=0.2\omega = 0.2 radians/second: T=2π0.2=2π1/5=10π secondsT = \frac{2\pi}{0.2} = \frac{2\pi}{1/5} = 10\pi \text{ seconds}

Calculating the value: T10×3.141631.416 secondsT \approx 10 \times 3.1416 \approx 31.416 \text{ seconds}

Summary of the Answers:

  1. The (X,Y)(X, Y) coordinates at t=8t = 8 seconds are approximately (0.292,9.996)(-0.292, 9.996) cm.
  2. The (X,Y)(X, Y) coordinates at t=20t = 20 seconds are approximately (6.536,7.568)(-6.536, -7.568) cm.
  3. The time taken to complete one full rotation is approximately 31.41631.416 seconds.

Would you like more details or have any questions about the steps?

Here are 5 related questions:

  1. What would be the (X,Y)(X, Y) coordinates at t=15t = 15 seconds?
  2. How would the solution change if the object had a different initial position?
  3. What is the physical significance of angular velocity in circular motion?
  4. How can we determine the speed of the object in its circular path?
  5. How does the radius affect the time taken to complete one full rotation?

Tip: In circular motion problems, always start by finding the angle covered over the time interval, as it directly determines the position of the object on the circle.

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Math Problem Analysis

Mathematical Concepts

Circular Motion
Parametric Equations
Angular Velocity

Formulas

Parametric equations of circular motion
Angular velocity formula
Angle displacement formula

Theorems

None

Suitable Grade Level

High School