Math Problem Statement

Given that AC and BD are diameters of circle O centered at E and are perpendicular, find the measures of the indicated angles and arcs.

Solution

The problem involves a circle with diameters ACAC and BDBD that intersect at point EE, and these diameters are perpendicular. This setup forms right angles at EE and divides the circle into four right-angled triangles.

Let's go through each question:

31. mAEDm\angle AED

Since ACAC and BDBD are diameters and are perpendicular, they form a right angle at EE. Thus: mAED=90m\angle AED = 90^\circ

32. mABm\overset{\frown}{AB}

The arc ABAB is intercepted by the central angle AEB\angle AEB, which measures 9090^\circ (since AEB\angle AEB is part of the perpendicular diameters). Therefore: mAB=90m\overset{\frown}{AB} = 90^\circ

33. mADCm\angle ADC

Since AA, DD, and CC are points on the circle and ACAC is a diameter, ADC\angle ADC is an inscribed angle that intercepts a semicircle (180° arc). By the inscribed angle theorem, an angle that intercepts a semicircle is a right angle: mADC=90m\angle ADC = 90^\circ

34. mBCDm\overset{\frown}{BCD}

The arc BCDBCD is the major arc that covers three of the four 90° quadrants in the circle. Thus: mBCD=270m\overset{\frown}{BCD} = 270^\circ

35. mBDCm\angle BDC

This is an inscribed angle that intercepts the arc BCBC, which is 90°. By the inscribed angle theorem, mBDCm\angle BDC is half of the intercepted arc: mBDC=902=45m\angle BDC = \frac{90^\circ}{2} = 45^\circ

Summary of Answers

  • 31. mAED=90m\angle AED = 90^\circ
  • 32. mAB=90m\overset{\frown}{AB} = 90^\circ
  • 33. mADC=90m\angle ADC = 90^\circ
  • 34. mBCD=270m\overset{\frown}{BCD} = 270^\circ
  • 35. mBDC=45m\angle BDC = 45^\circ

Would you like any additional details or explanations?


Related Questions:

  1. Why is an inscribed angle half of the intercepted arc's angle?
  2. What are the properties of diameters that intersect at right angles in a circle?
  3. How does the central angle relate to its intercepted arc in a circle?
  4. Can you apply the same concepts if the diameters were not perpendicular?
  5. What happens to inscribed angles in a circle when they intercept the same arc?

Tip: In a circle, an inscribed angle is always half the measure of the arc it intercepts. This is helpful for quickly finding angle measures based on arc lengths.

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Math Problem Analysis

Mathematical Concepts

Circle Geometry
Angles and Arcs in Circles

Formulas

Inscribed Angle = 1/2 * Intercepted Arc
Central Angle = Intercepted Arc

Theorems

Inscribed Angle Theorem
Properties of Perpendicular Diameters in Circles

Suitable Grade Level

Grades 9-10