Math Problem Statement
Solution
The problem involves a circle with diameters and that intersect at point , and these diameters are perpendicular. This setup forms right angles at and divides the circle into four right-angled triangles.
Let's go through each question:
31.
Since and are diameters and are perpendicular, they form a right angle at . Thus:
32.
The arc is intercepted by the central angle , which measures (since is part of the perpendicular diameters). Therefore:
33.
Since , , and are points on the circle and is a diameter, is an inscribed angle that intercepts a semicircle (180° arc). By the inscribed angle theorem, an angle that intercepts a semicircle is a right angle:
34.
The arc is the major arc that covers three of the four 90° quadrants in the circle. Thus:
35.
This is an inscribed angle that intercepts the arc , which is 90°. By the inscribed angle theorem, is half of the intercepted arc:
Summary of Answers
- 31.
- 32.
- 33.
- 34.
- 35.
Would you like any additional details or explanations?
Related Questions:
- Why is an inscribed angle half of the intercepted arc's angle?
- What are the properties of diameters that intersect at right angles in a circle?
- How does the central angle relate to its intercepted arc in a circle?
- Can you apply the same concepts if the diameters were not perpendicular?
- What happens to inscribed angles in a circle when they intercept the same arc?
Tip: In a circle, an inscribed angle is always half the measure of the arc it intercepts. This is helpful for quickly finding angle measures based on arc lengths.
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Math Problem Analysis
Mathematical Concepts
Circle Geometry
Angles and Arcs in Circles
Formulas
Inscribed Angle = 1/2 * Intercepted Arc
Central Angle = Intercepted Arc
Theorems
Inscribed Angle Theorem
Properties of Perpendicular Diameters in Circles
Suitable Grade Level
Grades 9-10
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