in 1195 chipper jones hit 23 homeruns 3 triples 22 doubles and 91 singles if he only had 524 at bats whats his slugging average

To calculate Chipper Jones' slugging percentage (or slugging average) for the 1995 season, we need to use the following formula:

\[
\text{Slugging Percentage (SLG)} = \frac{\text{Total Bases}}{\text{At Bats}}
\]

### Step 1: Calculate total bases
- **Singles**: Each single counts as 1 base. He hit 91 singles, so he gets \( 91 \times 1 = 91 \) bases.
- **Doubles**: Each double counts as 2 bases. He hit 22 doubles, so he gets \( 22 \times 2 = 44 \) bases.
- **Triples**: Each triple counts as 3 bases. He hit 3 triples, so he gets \( 3 \times 3 = 9 \) bases.
- **Home Runs**: Each home run counts as 4 bases. He hit 23 home runs, so he gets \( 23 \times 4 = 92 \) bases.

### Step 2: Add total bases
\[
\text{Total Bases} = 91 + 44 + 9 + 92 = 236
\]

### Step 3: Calculate the slugging percentage
Now, we divide the total bases by the number of at-bats (524):

\[
\text{SLG} = \frac{236}{524} \approx 0.450
\]

### Conclusion:
Chipper Jones' slugging percentage for the 1995 season was approximately **0.450**.

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Do you have any questions or want more details on this calculation? Here are 5 related questions to explore:

1. How does slugging percentage differ from batting average?
2. What is the highest slugging percentage in a single season?
3. How does on-base percentage (OBP) relate to slugging percentage?
4. What is the significance of slugging percentage in evaluating a player's performance?
5. How is total bases calculated for other types of hits (e.g., walks or hit by pitches)?

**Tip:** Slugging percentage is a powerful metric that measures the power of a hitter, reflecting how many bases a player averages per hit.

Learn how to calculate Chipper Jones' slugging percentage for the 1995 season based on his hits, including 23 home runs, 3 triples, 22 doubles, and 91 singles with 524 at-bats. This guide covers baseball statistics and arithmetic suitable for Grades 9-12.

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