Math Problem Statement

Check whether the following functions are continuous or not: 1) f(x, y, z) = x^2 + y^2 + z^2, 2) f(x, y) = yx^2 + xy^2, 3) f(x, y) = (x^3 - y^3)/(x + y), 4) f(x, y, z) = tan^{-1}(√x+√y+√z)/(√x+√y+√z)

Solution

Let's analyze the continuity of each function step by step:

1) f(x,y,z)=x2+y2+z2f(x, y, z) = x^2 + y^2 + z^2

This is a polynomial function in three variables. Polynomial functions are continuous everywhere, as they do not have any points of discontinuity. Therefore:

  • Conclusion: f(x,y,z)=x2+y2+z2f(x, y, z) = x^2 + y^2 + z^2 is continuous for all real values of x,y,zx, y, z.

2) f(x,y)=yx2+xy2f(x, y) = yx^2 + xy^2

This is a polynomial in two variables xx and yy, and polynomial functions are continuous everywhere, regardless of the values of xx and yy.

  • Conclusion: f(x,y)=yx2+xy2f(x, y) = yx^2 + xy^2 is continuous for all real values of xx and yy.

3) f(x,y)=x3y3x+yf(x, y) = \frac{x^3 - y^3}{x + y}

Here we have a rational function. Rational functions are continuous everywhere except where the denominator is zero. In this case, the function may have a discontinuity where x+y=0x + y = 0, which simplifies to y=xy = -x.

To analyze the potential discontinuity, let's check the behavior of the function as yxy \to -x. We use factorization:

x3y3=(xy)(x2+xy+y2)x^3 - y^3 = (x - y)(x^2 + xy + y^2)

Thus, the function becomes:

f(x,y)=(xy)(x2+xy+y2)x+yf(x, y) = \frac{(x - y)(x^2 + xy + y^2)}{x + y}

At y=xy = -x, this function simplifies by canceling out the common factors. Therefore, we can conclude that there is no actual discontinuity, and the function is continuous at all points, including y=xy = -x.

  • Conclusion: f(x,y)=x3y3x+yf(x, y) = \frac{x^3 - y^3}{x + y} is continuous everywhere.

4) f(x,y,z)=tan1(x+y+zx+y+z)f(x, y, z) = \tan^{-1}\left( \frac{\sqrt{x} + \sqrt{y} + \sqrt{z}}{\sqrt{x} + \sqrt{y} + \sqrt{z}} \right)

This function simplifies to:

f(x,y,z)=tan1(1)f(x, y, z) = \tan^{-1}(1)

Since tan1(1)\tan^{-1}(1) is a constant function (equal to π4\frac{\pi}{4}) and constant functions are continuous everywhere, this function is continuous for all real values of xx, yy, and zz.

  • Conclusion: f(x,y,z)=tan1(1)f(x, y, z) = \tan^{-1}(1) is continuous everywhere.

Summary

  1. f(x,y,z)=x2+y2+z2f(x, y, z) = x^2 + y^2 + z^2 is continuous.
  2. f(x,y)=yx2+xy2f(x, y) = yx^2 + xy^2 is continuous.
  3. f(x,y)=x3y3x+yf(x, y) = \frac{x^3 - y^3}{x + y} is continuous.
  4. f(x,y,z)=tan1(1)f(x, y, z) = \tan^{-1}(1) is continuous.

Would you like further details or explanations on any specific function?


Here are 5 related questions:

  1. How do you check for continuity of a function at a specific point?
  2. What types of functions are always continuous?
  3. How can we handle removable discontinuities in a function?
  4. What is the difference between pointwise and uniform continuity?
  5. How do multivariable limits relate to the continuity of functions?

Tip: Remember that polynomial functions are always continuous, and rational functions are continuous wherever their denominators are non-zero

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Math Problem Analysis

Mathematical Concepts

Continuity
Polynomial Functions
Rational Functions
Trigonometric Functions

Formulas

f(x, y, z) = x^2 + y^2 + z^2
f(x, y) = yx^2 + xy^2
f(x, y) = (x^3 - y^3)/(x + y)
f(x, y, z) = tan^{-1}(√x+√y+√z)/(√x+√y+√z)

Theorems

Continuity of Polynomial Functions
Continuity of Rational Functions
Simplification of Trigonometric Functions

Suitable Grade Level

Undergraduate