https://file.aiquickdraw.com/mathbot/file/1728264909769pj2rx7e4.jpg

Here are the results of dividing Channel 2 by Channel 1 for each frequency:

- **1 kHz**: 0.9888
- **100 kHz**: 0.9121
- **200 kHz**: 0.7849
- **300 kHz**: 0.6458
- **400 kHz**: 0.5361
- **500 kHz**: 0.4500
- **600 kHz**: 0.3861
- **700 kHz**: 0.3366
- **800 kHz**: 0.2941
- **900 kHz**: 0.2647
- **1000 kHz**: 0.2255
- **1100 kHz**: 0.2157
- **1200 kHz**: 0.1961
- **1300 kHz**: 0.1765
- **1400 kHz**: 0.1667
- **1500 kHz**: 0.1456
- **1600 kHz**: 0.1359
- **1700 kHz**: 0.1154
- **1800 kHz**: 0.1154

Would you like any further details or explanations?

Here are some questions for expanding your understanding:
1. How does the ratio of Channel 2 to Channel 1 change with increasing frequency?
2. What could be the physical explanation for the trend in the ratio values?
3. Can you calculate the average of the Channel 2 / Channel 1 ratios?
4. How would this data be affected if one of the channels was faulty?
5. Could the ratios be used to calculate another related property, such as impedance?

**Tip**: A decreasing ratio might indicate increasing energy losses or signal attenuation at higher frequencies.

Divide Channel 2 values by Channel 1 values for each frequency.

Learn how to calculate the ratio of Channel 2 to Channel 1 for frequencies ranging from 1 kHz to 1800 kHz. The solution covers key mathematical concepts like ratio and division. Suitable for high school students (Grades 9-12) with a detailed breakdown of each ratio.

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