Math Problem Statement

A forester is making a gasoline-oil mixture for a chainsaw engine. The forester has 3 gallons of a mixture that is 27 parts gasoline and 1 part oil. How many gallons of gasoline should the forester add to bring the mixture to 42 parts gasoline and 1 part oil? (Round your answer to two decimal places.)

Solution

To solve this problem, we need to adjust the gasoline-oil ratio from the current 27:1 to the desired 42:1 by adding more gasoline to the existing mixture. Here's a step-by-step solution:

Step 1: Determine the current amount of gasoline and oil

The forester has 3 gallons of a mixture with a ratio of 27 parts gasoline to 1 part oil. This means the total number of parts in the mixture is:

27+1=28 parts27 + 1 = 28 \text{ parts}

The fraction of gasoline in the mixture is:

2728\frac{27}{28}

So, the amount of gasoline in the current 3-gallon mixture is:

3×2728=8128 gallons3 \times \frac{27}{28} = \frac{81}{28} \text{ gallons}

Similarly, the amount of oil is:

3×128=328 gallons3 \times \frac{1}{28} = \frac{3}{28} \text{ gallons}

Step 2: Set up the equation for the desired ratio

Let xx be the number of gallons of gasoline to add. After adding xx gallons of gasoline, the new amount of gasoline will be:

8128+x gallons\frac{81}{28} + x \text{ gallons}

The amount of oil remains the same at 328\frac{3}{28} gallons.

We want the new gasoline-oil ratio to be 42:1, so we set up the ratio equation:

8128+x328=42\frac{\frac{81}{28} + x}{\frac{3}{28}} = 42

Step 3: Solve for xx

Simplify the equation by multiplying both sides by 328\frac{3}{28}:

8128+x=42×328\frac{81}{28} + x = 42 \times \frac{3}{28}

8128+x=12628\frac{81}{28} + x = \frac{126}{28}

Subtract 8128\frac{81}{28} from both sides:

x=126288128x = \frac{126}{28} - \frac{81}{28}

x=1268128=45281.61 gallonsx = \frac{126 - 81}{28} = \frac{45}{28} \approx 1.61 \text{ gallons}

Thus, the forester should add approximately 1.61 gallons of gasoline to achieve the desired 42:1 gasoline-oil ratio.

Would you like more details or have any questions?

Here are some related questions:

  1. How would the solution change if the initial ratio were different?
  2. What if the forester only had 2 gallons of the initial mixture?
  3. How does the ratio affect engine performance in a chainsaw?
  4. Can you derive a general formula for adjusting ratios by adding a component?
  5. What happens if oil is added instead of gasoline?

Tip: Always cross-check your ratios after solving to ensure the desired proportions are achieved!

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Math Problem Analysis

Mathematical Concepts

Ratios
Algebra
Proportions

Formulas

Gasoline-Oil Ratio Adjustment: \( \frac{\text{Current Gasoline}}{\text{Oil}} = \frac{27}{1} \) adjusted to \( \frac{\text{New Gasoline}}{\text{Oil}} = \frac{42}{1} \)

Theorems

Ratio Proportion Theorem

Suitable Grade Level

Grades 9-12