Math Problem Statement
A forester is making a gasoline-oil mixture for a chainsaw engine. The forester has 3 gallons of a mixture that is 27 parts gasoline and 1 part oil. How many gallons of gasoline should the forester add to bring the mixture to 42 parts gasoline and 1 part oil? (Round your answer to two decimal places.)
Solution
To solve this problem, we need to adjust the gasoline-oil ratio from the current 27:1 to the desired 42:1 by adding more gasoline to the existing mixture. Here's a step-by-step solution:
Step 1: Determine the current amount of gasoline and oil
The forester has 3 gallons of a mixture with a ratio of 27 parts gasoline to 1 part oil. This means the total number of parts in the mixture is:
The fraction of gasoline in the mixture is:
So, the amount of gasoline in the current 3-gallon mixture is:
Similarly, the amount of oil is:
Step 2: Set up the equation for the desired ratio
Let be the number of gallons of gasoline to add. After adding gallons of gasoline, the new amount of gasoline will be:
The amount of oil remains the same at gallons.
We want the new gasoline-oil ratio to be 42:1, so we set up the ratio equation:
Step 3: Solve for
Simplify the equation by multiplying both sides by :
Subtract from both sides:
Thus, the forester should add approximately 1.61 gallons of gasoline to achieve the desired 42:1 gasoline-oil ratio.
Would you like more details or have any questions?
Here are some related questions:
- How would the solution change if the initial ratio were different?
- What if the forester only had 2 gallons of the initial mixture?
- How does the ratio affect engine performance in a chainsaw?
- Can you derive a general formula for adjusting ratios by adding a component?
- What happens if oil is added instead of gasoline?
Tip: Always cross-check your ratios after solving to ensure the desired proportions are achieved!
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Math Problem Analysis
Mathematical Concepts
Ratios
Algebra
Proportions
Formulas
Gasoline-Oil Ratio Adjustment: \( \frac{\text{Current Gasoline}}{\text{Oil}} = \frac{27}{1} \) adjusted to \( \frac{\text{New Gasoline}}{\text{Oil}} = \frac{42}{1} \)
Theorems
Ratio Proportion Theorem
Suitable Grade Level
Grades 9-12