A car moving at a tangential velocity of 25.7 m/s travels around a curve with a circular radius of 39 m. ac=v2rDetermine the centripetal acceleration of the car.A.0.66 m/s2B.16.9 m/s2C.32.3 m/s2D.56 m/s2

To determine the centripetal acceleration, we can use the formula:

\[
a_c = \frac{v^2}{r}
\]

Where:
- \(v\) is the tangential velocity (25.7 m/s),
- \(r\) is the radius of the curve (39 m).

Substituting the given values into the formula:

\[
a_c = \frac{(25.7)^2}{39}
\]

Let's calculate that.The centripetal acceleration of the car is approximately \(16.94 \, \text{m/s}^2\), which rounds to \(16.9 \, \text{m/s}^2\).

Therefore, the correct answer is:

**B. 16.9 m/s²**

Do you want more details or have any questions?

Here are five related questions to further explore this topic:
1. How does increasing the radius of the curve affect the centripetal acceleration?
2. If the velocity of the car doubled, what would happen to the centripetal acceleration?
3. What is the role of centripetal force in circular motion?
4. How would the centripetal acceleration change if the car was moving on a sharper curve?
5. What are the real-world examples where centripetal acceleration is observed?

**Tip:** Centripetal acceleration always points towards the center of the circular path, even though the object is moving tangentially.

A car moving at a tangential velocity of 25.7 m/s travels around a curve with a circular radius of 39 m. Determine the centripetal acceleration of the car. A. 0.66 m/s² B. 16.9 m/s² C. 32.3 m/s² D. 56 m/s²

Find the centripetal acceleration of a car moving at 25.7 m/s around a curve with a radius of 39 m. This problem demonstrates the use of the centripetal acceleration formula a_c = v² / r and involves key concepts from circular motion physics. Suitable for students in Grades 9-12.

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