Let's break down and solve the problem presented in the image. The question is in Indonesian, and it can be translated as follows:

Problem:

A car is moving in a straight line with an initial velocity of 36 km/h. After covering a distance of 150 meters, the speed becomes 72 km/h.

A. What is the acceleration experienced by the car?
B. What is the time taken by the car to travel the distance?
C. Create a GUI based on the answers to this problem.
D. Write a program that matches the GUI created.

Let's solve parts A and B first.

Part A: Find the acceleration experienced by the car.

• Initial velocity (u): 36 km/h = $\frac{36 \times 1000}{3600} = 10 \, \text{m/s}$
• Final velocity (v): 72 km/h = $\frac{72 \times 1000}{3600} = 20 \, \text{m/s}$
• Distance (s): 150 m

To find the acceleration $a$, we can use the equation of motion:

$v^2 = u^2 + 2as$

Rearranging to find $a$:

$a = \frac{v^2 - u^2}{2s}$

Substitute the values:

$a = \frac{(20)^2 - (10)^2}{2 \times 150}$

Part B: Find the time taken by the car.

We can use the following kinematic equation to find the time $t$:

$v = u + at$

Rearrange to find $t$:

$t = \frac{v - u}{a}$

Let me calculate these now.### Part A: The acceleration experienced by the car is 1 m/s².

Part B:

The time taken by the car to travel the distance of 150 meters is 10 seconds.

Would you like more details on how these were calculated, or guidance on parts C and D regarding the GUI and program?

Here are 5 related questions that might deepen your understanding:

1. How can we derive other kinematic equations from the basic principles of motion?
2. What if the initial or final velocity was different—how would that affect the acceleration?
3. Can we calculate the car’s motion under a non-uniform acceleration?
4. What happens if there is resistance, like friction, acting on the car?
5. How would the calculation change if we measured velocity in meters per second from the start?

Tip: When converting units like km/h to m/s, always remember to divide by 3.6.