Math Problem Statement

Suppose that a customer is purchasing a car. He conducts an experiment in which he puts 10 gallons of gas in the car and drives it until it runs out of gas. He conducts this experiment 15 times on each car and records the number of miles driven. Car 1 Car 2 214 213 249 201 241 224 242 232 219 252 260 245 251 240 164 286 288 250 251 264 164 291 309 243 276 256 310 268 274 289

Solution

It looks like we have a dataset for two cars, where a customer measures the mileage after filling 10 gallons of gas in the car and driving until it runs out of fuel. This experiment is repeated 15 times for each car, and the number of miles driven is recorded.

Let's break down the dataIt looks like we have a dataset for two cars, where a customer measures the mileage after filling 10 gallons of gas in the car and driving until it runs out of fuel. This experiment is repeated 15 times for each car, and the number of miles driven is recorded.

Let's break down the

Car 1 (miles driven): 214, 249, 241, 242, 219, 260, 251, 164, 288, 251, 164, 309, 276, 310, 274

Car 2 (miles driven): 213, 201, 224, 232, 252, 245, 240, 286, 250, 264, 291, 243, 256, 268, 289

To analyze this data, let's compute the following:

  1. Mean mileage (average miles driven) for both cars.
  2. Variance and standard deviation, which gives us an idea of the spread or variability in the mileage.
  3. Range (the difference between the highest and lowest mileage).
  4. Comparison between the two cars to determine which car is more fuel-efficient on average and which one has more consistent performance.

I'll calculate these metrics now.Here are the key statistics for both cars based on the data provided:

Car 1:

  • Mean mileage: 247.47 miles
  • Standard deviation: 43.90 miles (indicating the spread of values from the mean)
  • Range: 146 miles (difference between the highest and lowest mileage)

Car 2:

  • Mean mileage: 250.27 miles
  • Standard deviation: 26.73 miles
  • Range: 90 miles

Comparison:

  • Average Mileage: Car 2 has a slightly higher average mileage than Car 1, but the difference is quite small (250.27 vs. 247.47 miles).
  • Consistency: Car 2 has a much lower standard deviation (26.73 miles) compared to Car 1 (43.90 miles), meaning that Car 2’s mileage is more consistent across trials.
  • Range: Car 1 has a wider range of values (146 miles) compared to Car 2 (90 miles), which suggests Car 1's mileage varies more.

Do you want further details or have any questions?

Here are five related questions:

  1. What does the variance tell us about the performance of each car?
  2. How can we interpret the range in relation to driving conditions?
  3. Which car might be more reliable based on consistency of performance?
  4. Could extreme values (like outliers) affect the decision on which car to choose?
  5. How would additional trials affect these statistics?

Tip: Standard deviation is a key indicator of consistency; lower values mean more stable performance.

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Math Problem Analysis

Mathematical Concepts

Statistics
Mean
Standard Deviation
Range
Variance

Formulas

Mean: (Σx) / n
Standard Deviation: √[Σ(x - μ)^2 / n]
Range: Max value - Min value
Variance: Σ(x - μ)^2 / n

Theorems

Central Limit Theorem
Law of Large Numbers

Suitable Grade Level

Grades 10-12