Math Problem Statement

Students in a camp were grouped into 3 groups, A, B, and C. The ratio of the number of students in group A to the total number of students in groups B and C was 4:5. The ratio of the number of students in group C to the total number of students in groups A and B was 2:3. (a) Find the ratio of the number of students in group A to the number of students in group B to the ratio of the number of students in group C. (b) If the number of students in group C was 38 less than the number of students in group A, how many students took part in the camp?

Solution

Let's solve the problem step by step.

Question Overview:

We are tasked with two main parts:

  1. Part (a): Find the ratio of the number of students in group AA to group BB to group CC.
  2. Part (b): Use the information provided to determine the total number of students in the camp if group CC has 38 fewer students than group AA.

Step-by-Step Solution:

Part (a): Finding the ratio of A:B:CA : B : C

  1. Ratio from AA to B+CB + C: The ratio of AA to B+CB + C is 4:54 : 5. Let the number of students in: A=4x,B+C=5xA = 4x, \quad B + C = 5x

  2. Ratio from CC to A+BA + B: The ratio of CC to A+BA + B is 2:32 : 3. Let the number of students in: C=2y,A+B=3yC = 2y, \quad A + B = 3y

  3. Express A+BA + B from the first relationship: From the first ratio, A=4xA = 4x and B+C=5xB + C = 5x. So, A+B=4x+B=3yandC=2y.A + B = 4x + B = 3y \quad \text{and} \quad C = 2y.

  4. Express BB and equate relationships: From B+C=5xB + C = 5x and C=2yC = 2y: B=5x2yB = 5x - 2y

  5. Combine to eliminate yy: From A+B=3yA + B = 3y: 4x+(5x2y)=3y4x + (5x - 2y) = 3y Simplify: 9x=5y9x = 5y Solve for yy in terms of xx: y=9x5y = \frac{9x}{5}

  6. Substitute yy back to find A:B:CA : B : C:

    • A=4xA = 4x
    • B=5x2y=5x2(9x5)=5x18x5=25x18x5=7x5B = 5x - 2y = 5x - 2\left(\frac{9x}{5}\right) = 5x - \frac{18x}{5} = \frac{25x - 18x}{5} = \frac{7x}{5}
    • C=2y=2(9x5)=18x5C = 2y = 2\left(\frac{9x}{5}\right) = \frac{18x}{5}

    The ratio of A:B:CA : B : C is: A:B:C=4x:7x5:18x5A : B : C = 4x : \frac{7x}{5} : \frac{18x}{5} Multiply through by 5 to eliminate fractions: A:B:C=20:7:18A : B : C = 20 : 7 : 18

Final Answer for (a):

A:B:C=20:7:18A : B : C = 20 : 7 : 18


Part (b): Total number of students in the camp

  1. Let the number of students in AA, BB, and CC be 20k20k, 7k7k, and 18k18k respectively (from the ratio 20:7:1820 : 7 : 18).

  2. It is given that the number of students in CC is 38 less than the number of students in AA: 18k=20k3818k = 20k - 38 Solve for kk: 18k20k=3818k - 20k = -38 2k=38k=19-2k = -38 \quad \Rightarrow \quad k = 19

  3. Find the total number of students: A=20k=20×19=380,B=7k=7×19=133,C=18k=18×19=342A = 20k = 20 \times 19 = 380, \quad B = 7k = 7 \times 19 = 133, \quad C = 18k = 18 \times 19 = 342 Total students: 380+133+342=855380 + 133 + 342 = 855

Final Answer for (b):

The total number of students in the camp is: 855855


Summary of Answers:

  1. Part (a): A:B:C=20:7:18A : B : C = 20 : 7 : 18
  2. Part (b): Total students = 855855

Would you like further clarifications or detailed explanations? 😊


Related Questions:

  1. What would happen to the ratio A:B:CA : B : C if the number of students in group CC was halved?
  2. Can we represent the problem graphically to visualize the ratios more effectively?
  3. What mathematical principles are used to solve such ratio problems?
  4. How do we verify that the ratios are consistent across all conditions?
  5. What if the number of students in BB was given directly? How would it affect the calculations?

Tip:

When solving ratio problems, always align your terms by introducing variables systematically to avoid confusion!

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Math Problem Analysis

Mathematical Concepts

Ratios and Proportions
Linear Equations

Formulas

Ratio simplification formulas

Theorems

Basic principles of proportionality

Suitable Grade Level

Grades 7-9