Math Problem Statement
0.50 mL of cooking oil is placed in the chamber of a constant-volume calorimeter filled with sufficient oxygen for the oil to be completely burned. The chamber is immersed in a water bath. The mass of the water bath is 2.15 kg. For the purpose of this analysis, the metal parts of the apparatus are modeled as equivalent to an additional 0.5 kg of water. The calorimeter is well-insulated, and initially the temperature throughout is 25°C. The oil is ignited by a spark, and when equilibrium is again attained, the calorie value of the cooking oil is -8.1 kcal/mL. Calculate temperature throughout, in °C, after equilibrium is once again attained.
Solution
We will use the principle of conservation of energy to solve this calorimetry problem. The heat released by the burning oil is absorbed by the water and the equivalent metal parts of the calorimeter.
Given data:
- Volume of oil: mL
- Caloric value of oil: kcal/mL (negative sign indicates heat released)
- Mass of water: kg
- Mass of equivalent metal parts: kg
- Initial temperature:
- Specific heat capacity of water: kcal/kg·°C
- Total mass of water and equivalent metal parts:
Step 1: Calculate the total heat released by burning oil
Step 2: Use heat transfer equation
Since the heat is fully absorbed by the water and calorimeter, we apply:
where
is heat absorbed,
is the total mass,
is the specific heat of water,
is the change in temperature.
Rearranging for :
Substituting values:
Step 3: Final Temperature
Final Answer:
The temperature after equilibrium is attained is approximately
Would you like me to break anything down further?
Here are five related questions you might find interesting:
- How would the final temperature change if the calorimeter had a different heat capacity?
- What happens if some heat is lost to the surroundings?
- How would the result change if we burned more oil?
- Can we use this method to determine the energy content of different fuels?
- How does a bomb calorimeter improve the accuracy of such experiments?
Tip: Always ensure the calorimeter is well-insulated to minimize heat loss and improve accuracy! 🔥
Ask a new question for Free
By Image
Drop file here or Click Here to upload
Math Problem Analysis
Mathematical Concepts
Heat Transfer
Energy Conservation
Calorimetry
Specific Heat Capacity
Formulas
Q_oil = caloric value × volume of oil
Q = m c ΔT
ΔT = Q / (m c)
T_final = T_initial + ΔT
Theorems
Principle of Conservation of Energy
Suitable Grade Level
Grades 10-12
Related Recommendation
Calculating Final Temperature of Heated Water with Given Efficiency
Total Heat Lost by Water as it Cools from 140°C to -10°C
Calculate Final Temperature of Calorimeter After Combustion of Dimethylphthalate
Final Temperature Calculation of Aluminum Block After Condensation
Calorimetry Problem: Determining Mass of Alcohol in a Calorimeter