Math Problem Statement
Solution
Let's solve the given problems step by step.
Soal 1
Given: The curve and the x-axis, over the interval .
Find: The area between the curve and the x-axis.
Solution
The formula to compute the area between a curve and the x-axis is:
Here, , and the interval is . First, we check where the curve crosses the x-axis by solving :
This can be solved to determine points of sign changes. Then, integrate separately where is positive or negative.
Soal 2
Given: is the velocity of a particle over .
Part (a): Total Displacement
The total displacement is the integral of the velocity function:
Substitute , and evaluate.
Part (b): Total Distance
To find the total distance, we integrate the absolute value of the velocity:
Identify when to check where the velocity changes sign. Solve:
Thus, split the integral into intervals , , and , adjusting for the sign of in each interval.
Soal 3
Given: .
Find: .
Solution
To differentiate , we use:
- Product Rule:
- Chain Rule for composite functions.
- Trigonometric Derivatives: Differentiating and related functions.
Let and .
-
Differentiate using the chain rule:
-
Differentiate using the chain and power rule.
Combine both results using the product rule to find .
Would you like step-by-step calculations for any of these problems? Let me know!
5 Related Questions:
- How do you calculate areas under a curve if the function crosses the x-axis?
- What is the difference between displacement and distance in kinematics?
- How do you solve integrals involving absolute values?
- How do you use the product rule for differentiation?
- How do you apply the chain rule to logarithmic and trigonometric functions?
Tip: When solving for total distance, always split the integral at points where the velocity changes sign to ensure you account for magnitude correctly.
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Math Problem Analysis
Mathematical Concepts
Integration (Definite Integrals)
Displacement and Total Distance in Kinematics
Differentiation: Chain Rule, Product Rule, Trigonometric Derivatives
Formulas
Area under a curve: A = ∫[a,b] |f(x)| dx
Displacement: ∫ v(t) dt
Total distance: ∫ |v(t)| dt
Chain Rule: d/dx [f(g(x))] = f'(g(x))·g'(x)
Product Rule: d/dx [u·v] = u'v + uv'
Theorems
Fundamental Theorem of Calculus
Rules of Differentiation
Absolute Value in Integrals
Suitable Grade Level
Undergraduate Mathematics or Advanced High School Calculus
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