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The problem in the image involves calculating the support reactions for a simply supported structure, which is statically determinate (isostatic). 

### Information from the image:
- The structure is supported at two points: A (a pinned support) and B (a roller support).
- A downward force of 23 kN is applied at the center (5 meters from the left side).
- A horizontal force of 5 kN is applied to the left side of the structure.
- The dimensions between the supports and the loads are clearly indicated, with a total length of 12 meters and distributed dimensions: 2 m, 8 m, and 2 m from the supports.

### Reactions:
We need to find:
- \( R_A^y \) (vertical reaction at point A)
- \( R_A^x \) (horizontal reaction at point A)
- \( R_B^y \) (vertical reaction at point B)

### Steps:
1. **Horizontal Equilibrium (ΣFₓ = 0):**
   \[
   R_A^x - 5 = 0 \quad \Rightarrow \quad R_A^x = 5 \, \text{kN}
   \]

2. **Vertical Equilibrium (ΣFᵧ = 0):**
   The total vertical forces should balance:
   \[
   R_A^y + R_B^y - 23 = 0 \quad \Rightarrow \quad R_A^y + R_B^y = 23 \, \text{kN}
   \]

3. **Moment Equilibrium (ΣM = 0):**
   Taking moments around point A:
   \[
   \text{Moment about A:} \quad -23 \times 5 + R_B^y \times 10 = 0
   \]
   Solving for \( R_B^y \):
   \[
   -115 + 10R_B^y = 0 \quad \Rightarrow \quad R_B^y = 11.5 \, \text{kN}
   \]

4. **Find \( R_A^y \):**
   From the vertical equilibrium equation:
   \[
   R_A^y + 11.5 = 23 \quad \Rightarrow \quad R_A^y = 23 - 11.5 = 11.5 \, \text{kN}
   \]

### Final Reactions:
- \( R_A^x = 5 \, \text{kN} \) (horizontal reaction at A)
- \( R_A^y = 11.5 \, \text{kN} \) (vertical reaction at A)
- \( R_B^y = 11.5 \, \text{kN} \) (vertical reaction at B)

Let me know if you would like further details or clarifications!

### Follow-up Questions:
1. How would the reaction forces change if the 23 kN force were shifted to the left?
2. What would happen if there was an additional vertical load between A and B?
3. How is the moment equation derived for point A?
4. Why is the structure considered isostatic?
5. Can you calculate the internal shear force at any point in the beam?

**Tip**: Always use moment equilibrium around a point with the least unknowns to simplify calculations.

Calcule las reacciones de vínculo de la siguiente estructura isostática con cargas de 23 kN y 5 kN, soportada en A y B con diferentes distancias y medidas especificadas en la figura.

Learn how to calculate support reactions for a simply supported isostatic structure subjected to vertical and horizontal forces of 23 kN and 5 kN, respectively. This problem involves the use of static equilibrium equations for horizontal and vertical forces as well as moment equilibrium to determine reactions at pinned and roller supports.

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