Considering only offices *with* a wait-tracking system, what is the *z*-score for the 6th patient in the sample (wait time = 37 minutes)?

If required, round your intermediate calculations and final answer to two decimal places.

*z*-score =

To calculate the *z*-score for the 6th patient with a wait time of 37 minutes, we need the following formula for the *z*-score:

\[
z = \frac{X - \mu}{\sigma}
\]

Where:
- \(X\) is the data point (wait time for the 6th patient, 37 minutes in this case),
- \(\mu\) is the mean (average) wait time for the sample,
- \(\sigma\) is the standard deviation of the wait times in the sample.

Since the mean (\(\mu\)) and standard deviation (\(\sigma\)) are not provided in the problem statement, we need that information to proceed with the calculation. Could you please provide the mean and standard deviation of the wait times, or would you like help calculating those values based on a dataset?

Feel free to ask any clarifications or provide details, and we can continue from there.

Here are 5 related questions to consider:
1. How does the *z*-score interpretation change based on the value?
2. What is the significance of a *z*-score being positive or negative?
3. How do you calculate the mean wait time for a set of data points?
4. Why is standard deviation important when calculating *z*-scores?
5. How would the calculation change if the wait time were 50 minutes instead of 37?

**Tip:** The *z*-score tells you how many standard deviations a data point is from the mean. It is a great tool for comparing different data points within the same distribution!

Considering only offices with a wait-tracking system, what is the z-score for the 6th patient in the sample (wait time = 37 minutes)?

Learn how to calculate the z-score for the 6th patient with a 37-minute wait time in a wait-tracking system. This problem involves key statistical concepts like the z-score formula and the properties of normal distribution, making it ideal for students in Grades 9-12.

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