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To find the x-component of the force acting on the block, we can use the formula:

\[
F_x = F \cdot \cos(\theta)
\]

Where:
- \( F_x \) is the x-component of the force,
- \( F = 177 \, \text{N} \) is the total force applied,
- \( \theta = 85^\circ \) is the angle between the force and the horizontal.

Now, I'll calculate the x-component.The x-component of the force acting on the block is approximately \( 15.43 \, \text{N} \).

Would you like further details or have any questions?

Here are 5 related questions:
1. What is the y-component of the force acting on the block?
2. How would the x-component change if the angle were 60° instead of 85°?
3. What is the resultant force on the block when considering both x and y components?
4. How do friction forces impact the movement of the block in this situation?
5. What if the block was pulled on an inclined plane—how would the components change?

**Tip:** Always use the cosine of the angle to calculate the horizontal (x) component and the sine for the vertical (y) component in force problems.

A block is pulled by a force of 177 N directed at a 85.0° angle from the horizontal. What is the x-component of the force acting on the block?

Explore how to calculate the x-component of a force when a block is pulled by a 177 N force at an 85° angle from the horizontal. This guide includes the use of the cosine function to decompose the force into its horizontal component.

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