Math Problem Statement

Suppose you wanted to build a telescope capable of resolving a planet the size of Earth that is 18 light-years away.   a. Calculate the angular diameter of Earth if it were that far. To see any detail on the surface, we would want to see an angular size about ten times smaller than this.   b. Calculate the diameter of a telescope that would be needed to resolve this angular size if ​observing at 560 nm. Is this feasible?   a. The angular diameter is  × 10-9 degree.   b. The diameter of the telescope would have to be D =    km.   It   (Click to select)   is   is not  feasible to build a telescope this size.

Solution

To solve this problem, we need to follow these steps:

Part (a): Calculating the Angular Diameter of Earth

The angular diameter θ\theta of an object is given by the formula:

θ=dD\theta = \frac{d}{D}

where:

  • dd is the actual diameter of the object.
  • DD is the distance to the object.

The diameter of Earth (dd) is approximately 12,742 km.

The distance to the object (DD) is 18 light-years. To convert this into kilometers: D=18×9.461×1012 kmD = 18 \times 9.461 \times 10^{12} \text{ km}

Thus, D=1.70298×1014 kmD = 1.70298 \times 10^{14} \text{ km}

Plugging in the values: θ=12,742 km1.70298×1014 km\theta = \frac{12,742 \text{ km}}{1.70298 \times 10^{14} \text{ km}}

θ7.485×1011 radians\theta \approx 7.485 \times 10^{-11} \text{ radians}

To convert radians to degrees, we use the conversion factor 1 radian=180π degrees1 \text{ radian} = \frac{180}{\pi} \text{ degrees}:

θ7.485×1011×180π\theta \approx 7.485 \times 10^{-11} \times \frac{180}{\pi}

θ4.29×109 degrees\theta \approx 4.29 \times 10^{-9} \text{ degrees}

So, the angular diameter of Earth if it were 18 light-years away is 4.29×109 degrees4.29 \times 10^{-9} \text{ degrees}.

Part (b): Calculating the Diameter of the Telescope

To resolve an angular size about ten times smaller, the desired angular resolution would be:

θdesired=4.29×109104.29×1010 degrees\theta_{desired} = \frac{4.29 \times 10^{-9}}{10} \approx 4.29 \times 10^{-10} \text{ degrees}

The angular resolution θres\theta_{res} of a telescope is given by:

θres=1.22λD\theta_{res} = 1.22 \frac{\lambda}{D}

where:

  • λ\lambda is the wavelength of light.
  • DD is the diameter of the telescope.

Rearranging to solve for DD:

D=1.22λθresD = 1.22 \frac{\lambda}{\theta_{res}}

Given: λ=560 nm=560×109 m\lambda = 560 \text{ nm} = 560 \times 10^{-9} \text{ m}

θres=4.29×1010 degrees×π180 radians/degree7.48×1012 radians\theta_{res} = 4.29 \times 10^{-10} \text{ degrees} \times \frac{\pi}{180} \text{ radians/degree} \approx 7.48 \times 10^{-12} \text{ radians}

Plugging in the values:

D=1.22560×1097.48×101291.32×103 mD = 1.22 \frac{560 \times 10^{-9}}{7.48 \times 10^{-12}} \approx 91.32 \times 10^3 \text{ m}

D91.32 kmD \approx 91.32 \text{ km}

So, the diameter of the telescope would have to be approximately 91.32 km.

Feasibility

A telescope with a diameter of 91.32 km is not feasible with current technology. It is far beyond the scale of any existing or planned telescopes.

Would you like more details or have any questions?

Here are some questions you might consider next:

  1. What are the limits of current telescope technology in terms of diameter?
  2. How do different wavelengths of light affect telescope resolution?
  3. What advancements in technology could make larger telescopes feasible?
  4. How does the atmosphere impact ground-based telescope observations?
  5. What are interferometric techniques, and how can they be used to achieve higher resolutions?

Tip: Understanding the principles of angular resolution and the limitations of current technology is essential when considering the feasibility of astronomical observations.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Optics
Astronomy

Formulas

Angular diameter formula: theta = d / D
Angular resolution formula: theta_res = 1.22 * lambda / D

Theorems

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Suitable Grade Level

Advanced College