The problem asks for the sample proportion $\hat{p}$, given a confidence interval for the proportion of accountants who double-check their work.

The confidence interval provided is $(0.89, 0.97)$.

To estimate the sample proportion $\hat{p}$, we typically use the midpoint of the confidence interval. This can be calculated as follows:

$\hat{p} = \frac{\text{lower bound} + \text{upper bound}}{2} = \frac{0.89 + 0.97}{2} = \frac{1.86}{2} = 0.93$

So, the sample proportion $\hat{p}$ is 0.93.

Would you like further clarification or details on how this is computed?

Here are five related questions to explore:

1. How is a confidence interval constructed in statistics?
2. What does the sample proportion represent in a survey?
3. How do you interpret a confidence interval in terms of probability?
4. What is the margin of error in a confidence interval?
5. How would increasing the sample size affect the width of the confidence interval?

Tip: The midpoint of the confidence interval is a good estimate of the sample proportion when no other data is provided.