Math Problem Statement

You purchased 5.0 kg of apples from Wollaston. You noticed that they used a spring scale with the smallest division of 18.6 g to © Macmillan Learn weigh them. What is the relative error in this weight measurement as a percentage? [For example, if you find it to be 1.2% you should enter 1.2 in the answer box.]

Solution

The relative error in a measurement is calculated as the ratio of the absolute uncertainty (smallest division of the scale) to the measured value, multiplied by 100 to convert it to a percentage.

Here’s how to calculate it:

  1. Absolute Uncertainty: This is the smallest division of the scale, which is 18.6g18.6 \, \text{g}.
  2. Measured Value: The weight of the apples, which is 5.0kg5.0 \, \text{kg} or 5000g5000 \, \text{g}.
  3. Relative Error Calculation:

Relative Error=(Absolute UncertaintyMeasured Value)×100\text{Relative Error} = \left( \frac{\text{Absolute Uncertainty}}{\text{Measured Value}} \right) \times 100

Substitute the values:

Relative Error=(18.65000)×100\text{Relative Error} = \left( \frac{18.6}{5000} \right) \times 100

Relative Error=0.372%\text{Relative Error} = 0.372\%

Answer:

The relative error in this weight measurement is 0.372%.

Would you like further details on this calculation, or do you have additional questions?


Related Questions:

  1. How would the relative error change if the apples weighed only 2.5 kg?
  2. What would be the relative error if the smallest division of the scale were 10 g?
  3. Why is relative error important in measurement?
  4. How can the precision of the scale affect the accuracy of the measured weight?
  5. How is absolute error different from relative error?

Tip:

Always check the units of measurement to ensure they align across your calculation, especially when dealing with relative errors.

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Math Problem Analysis

Mathematical Concepts

Measurement
Relative Error
Percentage

Formulas

Relative Error = (Absolute Uncertainty / Measured Value) × 100

Theorems

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Suitable Grade Level

Grades 9-12