Math Problem Statement

explain

Poynting vector for a plane wave in a lossy medium and calculating decibels of power loss over 1 meter.

Solution

The text in the image describes a relationship involving the Poynting vector for a plane wave propagating in a lossy medium and how to calculate the power loss in decibels over a distance of 1 meter.

Explanation:

  1. Poynting Vector: The Poynting vector represents the power per unit area carried by an electromagnetic wave. In a lossy medium (where the wave attenuates due to absorption or scattering), the power carried by the wave decreases as it propagates.

  2. Decibels of Power Loss: The decibels (dB) of power loss is a logarithmic measure that quantifies how much the power diminishes over a certain distance, here specified as 1 meter. The formula provided in the text is:

    Power Loss (dB)=10log10e2α8.68α\text{Power Loss (dB)} = 10 \log_{10} e^{2\alpha} \approx 8.68\alpha

    where:

    • α\alpha is the attenuation constant, which characterizes how quickly the wave's amplitude decreases with distance in the lossy medium.
    • ee is the base of the natural logarithm (approximately 2.718).
  3. Derivation and Meaning: The expression 10log10e2α10 \log_{10} e^{2\alpha} simplifies to approximately 8.68α8.68\alpha because log10(e)0.434\log_{10}(e) \approx 0.434. Thus, multiplying by 10 gives the coefficient 4.34, and since there is a factor of 2, it becomes approximately 8.68.

    This formula allows one to compute the power loss in decibels per meter for a given attenuation constant α\alpha.

Summary:

  • The text is about calculating power loss in a lossy medium for a plane wave.
  • The power loss in decibels over 1 meter is given by the formula 10log10e2α10 \log_{10} e^{2\alpha}, which simplifies to approximately 8.68α8.68\alpha.

Would you like further details or have any questions about this topic?

Related Questions:

  1. What is the Poynting vector and how is it derived?
  2. How does the attenuation constant α\alpha affect wave propagation in a medium?
  3. Why is power loss measured in decibels (dB)?
  4. How is the formula for power loss in decibels related to the exponential attenuation of waves?
  5. What are some practical applications of calculating power loss in lossy mediums?

Tip: When dealing with logarithmic expressions, remember that decibels are used to measure ratios and logarithms convert multiplication into addition, simplifying the analysis of power loss over large distances.

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Math Problem Analysis

Mathematical Concepts

Electromagnetic waves
Power loss
Logarithmic functions

Formulas

Power Loss (dB) = 10 log₁₀ e^(2α) ≈ 8.68α

Theorems

Poynting theorem
Logarithmic properties

Suitable Grade Level

Undergraduate level (Physics/Electrical Engineering)