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Let's analyze the problem:

- The auditorium has many seats, and **only 1/6** of them have been filled.
- Of the remaining open seats, **20%** have been reserved for special guests.
- We are asked to find what portion of the entire auditorium is still available for seating.

### Step 1: Seats that are filled
The fraction of seats that are filled is given as \( \frac{1}{6} \). Therefore, the **open seats** are the remaining fraction of the auditorium:
\[
1 - \frac{1}{6} = \frac{6}{6} - \frac{1}{6} = \frac{5}{6}
\]
So, \( \frac{5}{6} \) of the seats are open.

### Step 2: Seats reserved for special guests
Of the open seats, **20%** are reserved for special guests. To find out how many of the open seats are reserved, we calculate 20% of \( \frac{5}{6} \):
\[
\text{Reserved seats} = 0.20 \times \frac{5}{6} = \frac{20}{100} \times \frac{5}{6} = \frac{1}{5} \times \frac{5}{6} = \frac{1}{6}
\]

### Step 3: Remaining seats available for seating
The portion of the auditorium available for general seating is the open seats minus the reserved seats:
\[
\text{Available for seating} = \frac{5}{6} - \frac{1}{6} = \frac{4}{6

A large auditorium has many seats, and only 1/6 of them have been filled. Of the open seats, 20% have been reserved for special guests. What portion of the auditorium is available for seating?

Learn how to calculate the portion of an auditorium available for seating. This problem involves finding open seats using fractions and percentages. Suitable for students in Grades 5-7.

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