Math Problem Statement

A large auditorium has many seats, and only 1/6 of them have been filled. Of the open seats, 20% have been reserved for special guests. What portion of the auditorium is available for seating?

Solution

Let's analyze the problem:

  • The auditorium has many seats, and only 1/6 of them have been filled.
  • Of the remaining open seats, 20% have been reserved for special guests.
  • We are asked to find what portion of the entire auditorium is still available for seating.

Step 1: Seats that are filled

The fraction of seats that are filled is given as 16\frac{1}{6}. Therefore, the open seats are the remaining fraction of the auditorium: 116=6616=561 - \frac{1}{6} = \frac{6}{6} - \frac{1}{6} = \frac{5}{6} So, 56\frac{5}{6} of the seats are open.

Step 2: Seats reserved for special guests

Of the open seats, 20% are reserved for special guests. To find out how many of the open seats are reserved, we calculate 20% of 56\frac{5}{6}: Reserved seats=0.20×56=20100×56=15×56=16\text{Reserved seats} = 0.20 \times \frac{5}{6} = \frac{20}{100} \times \frac{5}{6} = \frac{1}{5} \times \frac{5}{6} = \frac{1}{6}

Step 3: Remaining seats available for seating

The portion of the auditorium available for general seating is the open seats minus the reserved seats: [ \text{Available for seating} = \frac{5}{6} - \frac{1}{6} = \frac{4}{6

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Math Problem Analysis

Mathematical Concepts

Fractions
Percentages

Formulas

Fraction of open seats = 1 - filled seats
Reserved seats = percentage of open seats

Theorems

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Suitable Grade Level

Grades 5-7