Math Problem Statement

Find the odds of each of the following events. (a)an event E with ​Pr(E)=2/9 (b)an event E with ​Pr(E)equals=0.40

Solution

The odds of an event are defined as the ratio of the probability that the event occurs to the probability that it does not occur. If P(E)P(E) is the probability of the event occurring, then the odds of the event EE are given by the formula:

Odds of E=P(E)1P(E)\text{Odds of } E = \frac{P(E)}{1 - P(E)}

Let's calculate the odds for both events:

(a) Event EE with P(E)=29P(E) = \frac{2}{9}

Odds of E=29129=2979=27\text{Odds of } E = \frac{\frac{2}{9}}{1 - \frac{2}{9}} = \frac{\frac{2}{9}}{\frac{7}{9}} = \frac{2}{7} So, the odds of event EE are 2:72:7.

(b) Event EE with P(E)=0.40P(E) = 0.40

Odds of E=0.4010.40=0.400.60=23\text{Odds of } E = \frac{0.40}{1 - 0.40} = \frac{0.40}{0.60} = \frac{2}{3} So, the odds of event EE are 2:32:3.

Summary:

  • (a) The odds of event EE with P(E)=29P(E) = \frac{2}{9} are 2:72:7.
  • (b) The odds of event EE with P(E)=0.40P(E) = 0.40 are 2:32:3.

Would you like further details or have any questions?

Here are 5 related questions to deepen your understanding:

  1. How would you calculate the odds if the probability of an event is 13\frac{1}{3}?
  2. What is the relationship between odds and probability?
  3. How would the odds change if P(E)=0.75P(E) = 0.75?
  4. How do the odds differ when P(E)=0.5P(E) = 0.5?
  5. Can odds be greater than 1? What does it mean when they are?

Tip: Odds greater than 1 indicate that the event is more likely to occur than not.

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Math Problem Analysis

Mathematical Concepts

Probability
Odds

Formulas

Odds of E = P(E) / (1 - P(E))

Theorems

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Suitable Grade Level

Grades 9-12