To find the odds in favor of event $A$, we use the following formula:

$\text{Odds in favor of } A = \frac{P(A)}{1 - P(A)}$

Given:

• $P(A) = 0.36$

Now, let's calculate the odds:

$\text{Odds in favor of } A = \frac{0.36}{1 - 0.36} = \frac{0.36}{0.64}$

Simplifying the fraction:

$\frac{0.36}{0.64} = 0.5625$

Therefore, the odds in favor of event $A$ are $0.5625$ or $\frac{9}{16}$ when expressed as a ratio. This can be interpreted as the odds being 9 to 16 in favor of event $A$.

Would you like more details or have any questions?

Here are 5 related questions:

1. What are the odds against event $A$?
2. How do you calculate the probability of event $A \cup B$ (union of $A$ and $B$)?
3. What is the probability that neither $A$ nor $B$ happens?
4. How are the odds in favor of an event different from the event's probability?
5. If the events $A$ and $B$ are independent, what does $P(A \cap B)$ become?

Tip: Odds represent the ratio of favorable to unfavorable outcomes, while probability focuses on favorable outcomes relative to the total possible outcomes.