The problem you're presenting involves calculating the number of apples that could still be consumed after 30% of them were found to be rotten. Let's break it down:

• The total number of apples is 10 dozen.
• 1 dozen = 12 apples, so 10 dozen = 10 × 12 = 120 apples.
• 30% of the apples are rotten, so 70% are still good.

To find the number of apples that can be consumed, we calculate 70% of 120 apples:

$70\% \text{ of } 120 = 0.70 \times 120 = 84 \text{ apples}.$

Thus, 84 apples can still be consumed.

Would you like further clarification on this or help with any other questions?

Here are some related questions to explore:

1. How would the calculation change if 50% of the apples were rotten?
2. If 40 apples were rotten instead, how many apples could be consumed?
3. What is the percentage of apples that could be consumed if only 10% were rotten?
4. How would you calculate the remaining apples if 60% were rotten?
5. What is the impact of different percentages of rotten apples on the number of apples consumed?

Tip: Always convert percentages into decimals when performing calculations. For example, 30% becomes 0.30, and 70% becomes 0.70 when multiplying.