Math Problem Statement

X P(X) -3 0.45 4 0.1 5 0.2 9 0.25 Start by entering the probability distribution into the calculator.

Press "STAT" then ENTER (or select Edit)

Enter the values for X in the first list and the probabilities in the second list.

Then 2nd MODE to exit the list.

Press "STAT" then > to highlight "CALC"

Select 1-var stats

FOr List: List 1 (2nd 1)

FreqList: L2 (2nd 2)

Then calculate

= Mean =

= Standard Deviation = (round to 2 decimal places)

Solution

To find the mean and standard deviation for this probability distribution using a calculator, follow these steps:

  1. Enter the data into your calculator:

    • Press STAT and then press ENTER (or select Edit).
    • Enter the X-values (-3, 4, 5, 9) into the first list L1.
    • Enter the corresponding probabilities (0.45, 0.1, 0.2, 0.25) into the second list L2.
    • Press 2nd then MODE to exit the list entry screen.
  2. Calculate 1-variable statistics:

    • Press STAT, then press the right arrow key to highlight CALC.
    • Select 1-Var Stats (usually option 1).
    • For the List:, enter L1 (press 2nd and then 1).
    • For the FreqList:, enter L2 (press 2nd and then 2).
    • Press ENTER to calculate.
  3. Results:

    • The calculator will display various statistics, including the mean and standard deviation.

Let's calculate the mean (μ\mu) and standard deviation (σ\sigma) manually as well to verify:

Mean Calculation:

μ=[X×P(X)]=(3×0.45)+(4×0.1)+(5×0.2)+(9×0.25)\mu = \sum [X \times P(X)] = (-3 \times 0.45) + (4 \times 0.1) + (5 \times 0.2) + (9 \times 0.25)

μ=(1.35)+(0.4)+(1)+(2.25)=2.3\mu = (-1.35) + (0.4) + (1) + (2.25) = 2.3

Standard Deviation Calculation:

σ=[P(X)×(Xμ)2]\sigma = \sqrt{\sum [P(X) \times (X - \mu)^2]}

Let's compute this.The calculated values are:

  • Mean (μ): 2.3
  • Standard Deviation (σ): 5.06 (rounded to two decimal places)

Would you like further details or have any questions?

Here are some related questions to expand your understanding:

  1. How would the mean change if one of the probabilities was altered?
  2. What does the standard deviation tell us about this data set?
  3. How do you interpret a negative X-value in terms of probability?
  4. Can you calculate variance from the standard deviation?
  5. How would this calculation change if all probabilities were the same?

Tip: The standard deviation is a measure of how spread out the values are from the mean. A higher value indicates more variability.

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Math Problem Analysis

Mathematical Concepts

Probability Distribution
Mean
Standard Deviation
Expected Value

Formulas

Mean (μ) = Σ[X * P(X)]
Standard Deviation (σ) = √Σ[P(X) * (X - μ)^2]

Theorems

Law of Total Expectation

Suitable Grade Level

Grades 10-12