The school canteen offers 4 types of viands, 1 plain rice, 2 types of dessert and 4 types of drinks.If a student wishes to eat, jn how many ways can he choose?

To find the number of ways a student can choose their meal, we need to calculate the total number of choices available for each category, assuming they choose one item from each category. Here's the breakdown:

- **Viands**: 4 types
- **Rice**: 1 type (plain rice)
- **Desserts**: 2 types
- **Drinks**: 4 types

The total number of ways the student can choose their meal is the product of all these options. Thus:

\[
\text{Total number of ways} = 4 \times 1 \times 2 \times 4 = 32
\]

So, the student can choose their meal in **32 different ways**.

Would you like further details on how combinations work, or have any other questions?

Here are 5 related questions to consider:
1. What if the student can choose 2 types of viands instead of 1?
2. How would the number of ways change if there were 3 types of desserts?
3. What if the student can choose to skip dessert or drink?
4. How would the combinations change if the student could choose 2 drinks?
5. How would the calculation change if there were 5 types of viands?

**Tip:** When calculating combinations or choices, multiplying the number of options in each category gives you the total number of combinations.

The school canteen offers 4 types of viands, 1 plain rice, 2 types of dessert, and 4 types of drinks. If a student wishes to eat, in how many ways can he choose?

Discover how to calculate the number of ways a student can choose a meal in a school canteen offering 4 types of viands, 1 plain rice, 2 types of dessert, and 4 types of drinks. This problem demonstrates the multiplication principle of counting and is suitable for students in Grades 5-7.

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