Math Problem Statement

P(X < 1/2 and Y < 1/2)

Solution

The image you uploaded shows a mathematical expression involving a probability statement and a double integral:

P(X<12 and Y<12)=012012f(x,y)dxdyP(X < \frac{1}{2} \text{ and } Y < \frac{1}{2}) = \int_0^{\frac{1}{2}} \int_0^{\frac{1}{2}} f(x, y) \, dx \, dy

This represents the probability that two continuous random variables XX and YY are both less than 1/21/2, given their joint probability density function f(x,y)f(x, y).

To break it down:

  1. The left side, P(X<12 and Y<12)P(X < \frac{1}{2} \text{ and } Y < \frac{1}{2}), is the probability that both XX and YY are less than 1/2.

  2. The right side shows the calculation of this probability using a double integral: 012012f(x,y)dxdy\int_0^{\frac{1}{2}} \int_0^{\frac{1}{2}} f(x, y) \, dx \, dy where f(x,y)f(x, y) is the joint probability density function of XX and YY. This integral computes the total probability over the region where both XX and YY lie between 0 and 1/2.

Would you like further details or have any questions about the interpretation? Here are some related questions:

  1. What is a joint probability density function?
  2. How do you evaluate a double integral in probability theory?
  3. What are the conditions for f(x,y)f(x, y) to be a valid joint density function?
  4. Can this integral be computed directly for specific forms of f(x,y)f(x, y)?
  5. How does this formula extend to other bounds or regions for XX and YY?

Tip: When working with joint probabilities, always ensure that the limits of integration correctly define the region of interest.

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Math Problem Analysis

Mathematical Concepts

Probability Theory
Joint Probability
Double Integrals

Formulas

P(X < 1/2 and Y < 1/2) = ∫_0^1/2 ∫_0^1/2 f(x, y) dx dy

Theorems

Joint Probability Density Function
Fundamental Theorem of Calculus

Suitable Grade Level

College level or advanced high school (Grades 11-12)