The employee codes consist of one or two uppercase letters followed by a digit. Let's break down the possible combinations:

Case 1: One uppercase letter followed by a digit

• The first part is one uppercase letter. There are 26 possible uppercase letters (A to Z).
• The second part is a digit from 0 to 9. There are 10 possible digits.

So, the total number of combinations for this case is: $26 \times 10 = 260$

Case 2: Two uppercase letters followed by a digit

• The first part consists of two uppercase letters. Each letter has 26 possible options, so the number of combinations for the two letters is: $26 \times 26 = 676$
• The second part is still a digit, which has 10 possibilities.

So, the total number of combinations for this case is: $676 \times 10 = 6760$

Total number of employee codes

To find the total number of employee codes, we sum the possibilities from both cases: $260 + 6760 = 7020$

So, the company has 7,020 available employee codes.

Would you like any further details on the solution or have any other questions? Here are some related questions for further exploration:

1. How would the number of employee codes change if the company allowed lowercase letters as well?
2. What is the total number of possible codes if the digit range is expanded from 0-9 to 0-99?
3. How many employee codes would there be if the company allowed codes to be three characters long (with either one or two letters)?
4. How does the total number of codes change if the company requires the second part of the code to be a two-digit number instead of a single digit?
5. What would happen to the total number of employee codes if the company restricted the first part of the code to just one letter?

Tip: When dealing with combinations, always remember to multiply the possibilities for each independent part of the code.