Math Problem Statement

The terminal arms of angles in standard position pass through the following points. Find the measure of each angle in radians, to the nearest hundredth. Points: a) (-3, 14), b) (6, 7), c) (1, 9), d) (-5, -18), e) (2, 3), f) (4, -20).

Solution

To solve this problem, we calculate the angle θ\theta in radians for each point using the formula:

θ=arctan(yx)\theta = \arctan\left(\frac{y}{x}\right)

Key Considerations:

  1. The quadrant determines the angle's sign and the range of θ\theta.
  2. Adjust θ\theta as needed to ensure it lies within [0,2π)[0, 2\pi) for standard position.

Calculations:

Let's compute each one.

a) (3,14)(-3, 14)

  • x=3,y=14x = -3, y = 14 θ=arctan(143)=arctan(4.67)\theta = \arctan\left(\frac{14}{-3}\right) = \arctan(-4.67) This point is in the second quadrant, so: θ=π+arctan(4.67)1.93radians.\theta = \pi + \arctan(-4.67) \approx 1.93 \, \text{radians}.

b) (6,7)(6, 7)

  • x=6,y=7x = 6, y = 7 θ=arctan(76)arctan(1.167)0.86radians.\theta = \arctan\left(\frac{7}{6}\right) \approx \arctan(1.167) \approx 0.86 \, \text{radians}.

c) (1,9)(1, 9)

  • x=1,y=9x = 1, y = 9 θ=arctan(91)=arctan(9)1.46radians.\theta = \arctan\left(\frac{9}{1}\right) = \arctan(9) \approx 1.46 \, \text{radians}.

d) (5,18)(-5, -18)

  • x=5,y=18x = -5, y = -18 θ=arctan(185)=arctan(3.6)\theta = \arctan\left(\frac{-18}{-5}\right) = \arctan(3.6) This point is in the third quadrant, so: θ=π+arctan(3.6)4.25radians.\theta = \pi + \arctan(3.6) \approx 4.25 \, \text{radians}.

e) (2,3)(2, 3)

  • x=2,y=3x = 2, y = 3 θ=arctan(32)=arctan(1.5)0.98radians.\theta = \arctan\left(\frac{3}{2}\right) = \arctan(1.5) \approx 0.98 \, \text{radians}.

f) (4,20)(4, -20)

  • x=4,y=20x = 4, y = -20 θ=arctan(204)=arctan(5)\theta = \arctan\left(\frac{-20}{4}\right) = \arctan(-5) This point is in the fourth quadrant, so: θ=2π+arctan(5)4.92radians.\theta = 2\pi + \arctan(-5) \approx 4.92 \, \text{radians}.

Final Results (to nearest hundredth):

a) 1.93radians1.93 \, \text{radians}
b) 0.86radians0.86 \, \text{radians}
c) 1.46radians1.46 \, \text{radians}
d) 4.25radians4.25 \, \text{radians}
e) 0.98radians0.98 \, \text{radians}
f) 4.92radians4.92 \, \text{radians}

Would you like step-by-step verification or further clarification?


Related Questions:

  1. How is the arctangent function modified in different quadrants?
  2. Why is the angle shifted by π\pi in the second and third quadrants?
  3. How can this process be applied to find angles for 3D coordinates?
  4. What are the properties of the tangent function used in these calculations?
  5. How can calculators be used efficiently to find angles in radians?

Tip: Always verify which quadrant a point lies in before applying trigonometric functions.

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Math Problem Analysis

Mathematical Concepts

Trigonometry
Radians
Arctangent Function
Coordinate Geometry

Formulas

\( \theta = \arctan\left(\frac{y}{x}\right) \)
Angle adjustments based on quadrant

Theorems

Arctangent and Quadrant Adjustment

Suitable Grade Level

Grades 10-12