Math Problem Statement
The mean finish time for a yearly amateur auto race was 185.84 minutes with a standard deviation of 0.377 minute. The winning car, driven by Alex, finished in 184.98 minutes. The previous year's race had a mean finishing time of 111.6 with a standard deviation of 0.146 minute. The winning car that year, driven by Sally, finished in 111.24 minutes. Find their respective z-scores. Who had the more convincing victory?
Solution
To determine who had the more convincing victory, we need to calculate the z-scores for both Alex's and Sally's finishing times in their respective races.
Formula for Z-Score:
Where:
- is the individual score (finishing time in this case),
- is the mean,
- is the standard deviation.
1. Alex's Z-Score:
For Alex, we have:
- minutes,
- minutes,
- minute.
Now, calculating Alex's z-score:
2. Sally's Z-Score:
For Sally, we have:
- minutes,
- minutes,
- minute.
Now, calculating Sally's z-score:
Interpretation:
- Z-scores indicate how many standard deviations away a score is from the mean.
- The lower the z-score, the further away from the mean (in this case, faster relative to the average) the individual is.
Since Sally's z-score (-2.47) is lower than Alex's z-score (-2.28), Sally's performance was more statistically exceptional, meaning Sally had the more convincing victory.
Would you like any further details or have any questions?
Related Questions:
- What does a negative z-score signify in this context?
- How do z-scores help in comparing performances across different distributions?
- Can we use z-scores to compare athletes from different sports or competitions?
- What would a z-score of 0 indicate in a race?
- How does the standard deviation affect the interpretation of z-scores?
Tip:
Z-scores are particularly useful when comparing performances across different events with varying averages and spreads, as they standardize different datasets.
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Math Problem Analysis
Mathematical Concepts
Statistics
Z-scores
Standard Deviation
Formulas
Z-score formula: z = (x - μ) / σ
Theorems
-
Suitable Grade Level
Grades 10-12
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