Math Problem Statement

The mean finish time for a yearly amateur auto race was 185.84 minutes with a standard deviation of 0.377 minute. The winning​ car, driven by Alex​, finished in 184.98 minutes. The previous​ year's race had a mean finishing time of 111.6 with a standard deviation of 0.146 minute. The winning car that​ year, driven by Sally​, finished in 111.24 minutes. Find their respective​ z-scores. Who had the more convincing​ victory?

Solution

To determine who had the more convincing victory, we need to calculate the z-scores for both Alex's and Sally's finishing times in their respective races.

Formula for Z-Score:

z=xμσz = \frac{x - \mu}{\sigma} Where:

  • xx is the individual score (finishing time in this case),
  • μ\mu is the mean,
  • σ\sigma is the standard deviation.

1. Alex's Z-Score:

For Alex, we have:

  • x=184.98x = 184.98 minutes,
  • μ=185.84\mu = 185.84 minutes,
  • σ=0.377\sigma = 0.377 minute.

Now, calculating Alex's z-score: zA=184.98185.840.377=0.860.3772.28z_A = \frac{184.98 - 185.84}{0.377} = \frac{-0.86}{0.377} \approx -2.28

2. Sally's Z-Score:

For Sally, we have:

  • x=111.24x = 111.24 minutes,
  • μ=111.6\mu = 111.6 minutes,
  • σ=0.146\sigma = 0.146 minute.

Now, calculating Sally's z-score: zS=111.24111.60.146=0.360.1462.47z_S = \frac{111.24 - 111.6}{0.146} = \frac{-0.36}{0.146} \approx -2.47

Interpretation:

  • Z-scores indicate how many standard deviations away a score is from the mean.
  • The lower the z-score, the further away from the mean (in this case, faster relative to the average) the individual is.

Since Sally's z-score (-2.47) is lower than Alex's z-score (-2.28), Sally's performance was more statistically exceptional, meaning Sally had the more convincing victory.


Would you like any further details or have any questions?

Related Questions:

  1. What does a negative z-score signify in this context?
  2. How do z-scores help in comparing performances across different distributions?
  3. Can we use z-scores to compare athletes from different sports or competitions?
  4. What would a z-score of 0 indicate in a race?
  5. How does the standard deviation affect the interpretation of z-scores?

Tip:

Z-scores are particularly useful when comparing performances across different events with varying averages and spreads, as they standardize different datasets.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Statistics
Z-scores
Standard Deviation

Formulas

Z-score formula: z = (x - μ) / σ

Theorems

-

Suitable Grade Level

Grades 10-12