The Length of a rectangle is 3 inches less than 4 times the width. if the perimeter is 55 inches, what is the width of the rectangle 

Let's solve the problem step by step.

### Given:
- Let the width of the rectangle be \( w \) inches.
- The length of the rectangle is 3 inches less than 4 times the width, so the length can be expressed as \( 4w - 3 \) inches.
- The perimeter of the rectangle is 55 inches.

### Formula for the Perimeter of a Rectangle:
The perimeter \( P \) of a rectangle is given by:
\[
P = 2(\text{Length} + \text{Width})
\]
Substituting the given values:
\[
55 = 2((4w - 3) + w)
\]

### Simplify and Solve for \( w \):
\[
55 = 2(4w - 3 + w)
\]
\[
55 = 2(5w - 3)
\]
\[
55 = 10w - 6
\]
Add 6 to both sides:
\[
61 = 10w
\]
Divide both sides by 10:
\[
w = 6.1 \text{ inches}
\]

### Final Answer:
The width of the rectangle is **6.1 inches**.

Would you like more details on this solution, or do you have any further questions?

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Here are 5 related questions you might find interesting:
1. What would the length of the rectangle be based on the width found?
2. How would the perimeter change if the width were increased by 2 inches?
3. What would happen to the perimeter if the length were doubled?
4. How would you find the area of this rectangle?
5. If the perimeter was increased by 10 inches, what would the new width be?

**Tip:** Always check your solutions by plugging the values back into the original equations to ensure accuracy.

Learn how to calculate the width of a rectangle when given its perimeter of 55 inches and the relationship between its width and length. This problem involves basic geometry and algebra, suitable for Grades 7-9 students.

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