To determine the width of the Olympic-sized pool, we use the fact that the two pools are similar. Similarity means their corresponding dimensions are proportional.

Given Information:

1. LeJuan's pool:
   • Length = 30 m
   • Width = 8 m
2. Olympic-sized pool:
   • Length = 50 m
   • Width = unknown (let's call it $x$)

Step 1: Set up the proportion

The ratio of the lengths of the two pools equals the ratio of their widths because the pools are similar:

$\frac{\text{Width of LeJuan's pool}}{\text{Length of LeJuan's pool}} = \frac{\text{Width of Olympic-sized pool}}{\text{Length of Olympic-sized pool}}$

Substitute the known values:

$\frac{8}{30} = \frac{x}{50}$

Step 2: Solve for $x$ (width of the Olympic pool)

Cross-multiply to isolate $x$:

$8 \cdot 50 = 30 \cdot x$

$400 = 30x$

Divide both sides by 30:

$x = \frac{400}{30} \approx 13.33$

Step 3: Round to the nearest meter

To the nearest meter:

$x \approx 13 \, \text{m}$

Final Answer:

The width of the Olympic-sized pool is approximately 13 meters.

Would you like a detailed explanation of why proportions work here? Let me know if you have any questions!

Related Questions:

1. What are the dimensions of a standard Olympic-sized swimming pool?
2. How do you determine if two shapes are similar?
3. If LeJuan’s pool had a length of 40 m, what would its width be under the same proportion?
4. Can you calculate the area of the Olympic-sized pool based on its dimensions?
5. If LeJuan's pool and the Olympic-sized pool were squares instead, how would the problem change?

Tip: When solving proportions, always make sure corresponding parts match up (e.g., widths with widths and lengths with lengths).