Let's solve this step by step:

1. For Machine A:

   • Widgets produced: 36
   • Time taken: 9 hours
   • Rate of production: $\frac{36 \text{ widgets}}{9 \text{ hours}} = 4 \text{ widgets per hour}$

2. For Machine B:

   • Widgets produced: 30
   • Time taken: 6 hours
   • Rate of production: $\frac{30 \text{ widgets}}{6 \text{ hours}} = 5 \text{ widgets per hour}$

3. For Machine C:

   • Widgets produced: 60
   • Time taken: 10 hours
   • Rate of production: $\frac{60 \text{ widgets}}{10 \text{ hours}} = 6 \text{ widgets per hour}$

Summary:

• Machine A produces 4 widgets per hour.
• Machine B produces 5 widgets per hour.
• Machine C produces 6 widgets per hour.

Machine C is the fastest, producing 6 widgets per hour.

Do you need more details on this or have any further questions?
Here are 5 related questions to consider:

1. If the machines ran for 24 hours, how many widgets would each produce?
2. What would happen if the time for Machine C was reduced to 8 hours?
3. How can you calculate the efficiency of each machine?
4. What if the machines had different downtimes? How would you account for that?
5. What is the combined widget production rate of all machines?

Tip: Always divide the number of outputs by the time to find the rate of production.