Math Problem Statement

A student is taking an advanced anatomy class in which the midterm and final exams are both worth 40% each and homework is worth 20% of his final grade. On 100-point scale, his midterm exam score was 87 , his homework average score was 88 , and his final exam score was 83 . On a 100-point scale, what is the student’s overall average for the class? His overall average is % Round to the nearest tenth as needed. The student was hoping to get a 4.0 in the class, which requires an overall score of 92% or higher. What score would he have needed on the final exam to get a 4.0 in the class? % Enter “none” if it is not possible

Solution

To find the student’s overall average, we use the weights provided for each component of the class:

  • Midterm exam: 40% of the final grade.
  • Homework: 20% of the final grade.
  • Final exam: 40% of the final grade.

Step 1: Calculate the weighted average

The formula for the overall average is:

Overall average=(Midterm score×0.40)+(Homework score×0.20)+(Final exam score×0.40)\text{Overall average} = (\text{Midterm score} \times 0.40) + (\text{Homework score} \times 0.20) + (\text{Final exam score} \times 0.40)

Substitute the given scores:

Overall average=(87×0.40)+(88×0.20)+(83×0.40)\text{Overall average} = (87 \times 0.40) + (88 \times 0.20) + (83 \times 0.40)

Now, I'll calculate that.

87×0.40=34.887 \times 0.40 = 34.8 88×0.20=17.688 \times 0.20 = 17.6 83×0.40=33.283 \times 0.40 = 33.2

Now sum these values:

34.8+17.6+33.2=85.634.8 + 17.6 + 33.2 = 85.6

The student’s overall average is 85.6%.

Step 2: Determine if it is possible to get a 4.0 (92% or higher)

Next, we want to know what score the student would need on the final exam to achieve an overall average of 92%. The midterm and homework scores remain the same, so we can set up an equation where xx is the final exam score:

Overall average=(87×0.40)+(88×0.20)+(x×0.40)\text{Overall average} = (87 \times 0.40) + (88 \times 0.20) + (x \times 0.40)

We want the overall average to be 92:

92=(87×0.40)+(88×0.20)+(x×0.40)92 = (87 \times 0.40) + (88 \times 0.20) + (x \times 0.40)

We already know that:

(87×0.40)+(88×0.20)=34.8+17.6=52.4(87 \times 0.40) + (88 \times 0.20) = 34.8 + 17.6 = 52.4

So the equation becomes:

92=52.4+(x×0.40)92 = 52.4 + (x \times 0.40)

Now solve for xx:

9252.4=x×0.4092 - 52.4 = x \times 0.40 39.6=x×0.4039.6 = x \times 0.40 x=39.60.40=99x = \frac{39.6}{0.40} = 99

So the student would have needed to score 99% on the final exam to get a 4.0 in the class.

Conclusion:

  • The student’s overall average is 85.6%.
  • The score needed on the final exam to get a 4.0 is 99%.

Let me know if you'd like more details, or if you have any questions!


Here are 5 related questions:

  1. What if the student’s midterm score was 90? How would that change their final grade?
  2. How would the overall average change if homework were worth 30% instead of 20%?
  3. What is the impact on the final grade if the final exam score were 5 points higher?
  4. How could improving homework scores affect the overall average in a different scenario?
  5. What would the student’s grade be if only the midterm and final exams were considered?

Tip: Always check the weight of each component in your course to understand how it affects your final grade!

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Math Problem Analysis

Mathematical Concepts

Weighted Averages
Basic Algebra

Formulas

Overall average = (Midterm score × 0.40) + (Homework score × 0.20) + (Final exam score × 0.40)
x = (Desired overall score - Contribution of other components) / Weight of the final exam

Theorems

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Suitable Grade Level

Grades 9-12