A student is taking an advanced anatomy class in which the midterm and final exams are both worth 40%
each and homework is worth 20%
of his final grade. On 100-point scale, his midterm exam score was 87
, his homework average score was 88
, and his final exam score was 83
.
On a 100-point scale, what is the student’s overall average for the class?
His overall average is
%
Round to the nearest tenth as needed.
The student was hoping to get a 4.0 in the class, which requires an overall score of 92%
or higher. What score would he have needed on the final exam to get a 4.0 in the class?
%
Enter “none” if it is not possible

To find the student’s overall average, we use the weights provided for each component of the class:

- Midterm exam: 40% of the final grade.
- Homework: 20% of the final grade.
- Final exam: 40% of the final grade.

### Step 1: Calculate the weighted average

The formula for the overall average is:

\[
\text{Overall average} = (\text{Midterm score} \times 0.40) + (\text{Homework score} \times 0.20) + (\text{Final exam score} \times 0.40)
\]

Substitute the given scores:

\[
\text{Overall average} = (87 \times 0.40) + (88 \times 0.20) + (83 \times 0.40)
\]

Now, I'll calculate that.

\[
87 \times 0.40 = 34.8
\]
\[
88 \times 0.20 = 17.6
\]
\[
83 \times 0.40 = 33.2
\]

Now sum these values:

\[
34.8 + 17.6 + 33.2 = 85.6
\]

The student’s overall average is **85.6%**.

### Step 2: Determine if it is possible to get a 4.0 (92% or higher)

Next, we want to know what score the student would need on the final exam to achieve an overall average of 92%. The midterm and homework scores remain the same, so we can set up an equation where \( x \) is the final exam score:

\[
\text{Overall average} = (87 \times 0.40) + (88 \times 0.20) + (x \times 0.40)
\]

We want the overall average to be 92:

\[
92 = (87 \times 0.40) + (88 \times 0.20) + (x \times 0.40)
\]

We already know that:

\[
(87 \times 0.40) + (88 \times 0.20) = 34.8 + 17.6 = 52.4
\]

So the equation becomes:

\[
92 = 52.4 + (x \times 0.40)
\]

Now solve for \( x \):

\[
92 - 52.4 = x \times 0.40
\]
\[
39.6 = x \times 0.40
\]
\[
x = \frac{39.6}{0.40} = 99
\]

So the student would have needed to score **99%** on the final exam to get a 4.0 in the class.

### Conclusion:

- The student’s overall average is **85.6%**.
- The score needed on the final exam to get a 4.0 is **99%**.

Let me know if you'd like more details, or if you have any questions!

---

Here are 5 related questions:
1. What if the student’s midterm score was 90? How would that change their final grade?
2. How would the overall average change if homework were worth 30% instead of 20%?
3. What is the impact on the final grade if the final exam score were 5 points higher?
4. How could improving homework scores affect the overall average in a different scenario?
5. What would the student’s grade be if only the midterm and final exams were considered?

**Tip:** Always check the weight of each component in your course to understand how it affects your final grade!

A student is taking an advanced anatomy class in which the midterm and final exams are both worth 40% each and homework is worth 20% of his final grade. On a 100-point scale, his midterm exam score was 87, his homework average score was 88, and his final exam score was 83. On a 100-point scale, what is the student’s overall average for the class? His overall average is %. Round to the nearest tenth as needed. The student was hoping to get a 4.0 in the class, which requires an overall score of 92% or higher. What score would he have needed on the final exam to get a 4.0 in the class?

Find out how to calculate the overall grade based on weighted scores for midterms, homework, and final exams. This example covers a student's midterm score of 87, homework average of 88, and final exam score of 83. Also, discover the required final exam score to achieve a 4.0 GPA in this advanced class.

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