Let's solve the problem step by step.

Problem Analysis:

The force required to start moving the box is equal to the maximum static friction force, which is given by the formula: $F_{\text{friction}} = \mu_s \cdot F_N$ Where:

• $\mu_s$ is the coefficient of static friction ($0.35$).
• $F_N$ is the normal force, which is equal to the weight of the box ($F_N = W$) if the surface is horizontal.

Given: $F_{\text{friction}} = 350 \, \text{N}, \quad \mu_s = 0.35$

We are solving for the weight of the box ($W$).

Step 1: Rearrange the formula

$F_{\text{friction}} = \mu_s \cdot W$ Rearranging for $W$: $W = \frac{F_{\text{friction}}}{\mu_s}$

Step 2: Substitute the values

$W = \frac{350}{0.35}$

Step 3: Perform the calculation

$W = 1000 \, \text{N}$

Final Answer:

The weight of the box is 1000 N.

Let me know if you would like a detailed breakdown of the concept or additional help!

5 Related Questions:

1. How does the coefficient of static friction change with different surfaces?
2. If the coefficient of static friction was 0.4, what would the weight of the box be?
3. What is the difference between static friction and kinetic friction?
4. How does the angle of incline affect the normal force acting on an object?
5. What is the relationship between weight and mass? How do you calculate mass from weight?

Tip:

Always ensure units are consistent when solving physics problems!