You can store 2 L of liquid. The average soda output of a client is 0.3 L, the average water volume is 0.1 L. The ratio of water to soda is 3:7 on average, every 12 minutes a guest will use you. 2 hour dinner party how much water will you need to hold.

To determine how much water you will need to hold during a 2-hour dinner party, let's break down the information:

1. **Total time**: 2 hours = 120 minutes.
2. **Time per guest**: A guest uses the dispenser every 12 minutes.
3. **Number of uses**: \( \frac{120}{12} = 10 \) uses.
4. **Ratio of water to soda**: 3:7.

### Step 1: Calculate the total number of portions (water + soda) per guest.
The ratio 3:7 means for every 10 parts, 3 are water and 7 are soda.

### Step 2: Calculate the amount of liquid per use.
- Soda per guest: \( 0.3 \, L \)
- Water per guest: \( 0.1 \, L \)

Since the ratio is 3:7, 30% of the total liquid consumed is water.

### Step 3: Calculate the total water used.
- Total liquid per guest: \( 0.3 + 0.1 = 0.4 \, L \).
- For 10 uses: \( 10 \times 0.4 \, L = 4.0 \, L \) total.
- Water: \( 30\% \) of 4.0 L \( = 0.3 \times 4.0 = 1.2 \, L \).

### Conclusion
You will need to hold **1.2 L of water** for a 2-hour dinner party.

Would you like more details, or have any questions?

Here are some related questions:
1. How does the calculation change with different ratios of water to soda?
2. What if a guest uses more or less than 0.3 L of soda on average?
3. How would a longer dinner party affect the total water required?
4. What if the frequency of guest usage changes?
5. How does the total capacity of 2 L affect the overall operation?

**Tip:** Always calculate the exact ratio before multiplying to ensure accurate distributions.

Learn how to calculate the amount of water needed for a dinner party where guests consume soda and water from a dispenser. This problem involves understanding ratios, unit conversions, and calculating total liquid consumption per guest over a specified time period. Suitable for students in Grades 7-9.

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